How many moles in 4 g of Ca3N2? .027 mol .613 mol 2.05 mol .760 mol

A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.

Lilit [14]

Answer:

The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

$\frac{V1}{T1} = \frac{V2}{T2}$

Solve for V2

V2 = $\frac{V1T2}{T1}$

3.- Substitution

V2 = $\frac{(42)(233)}{293}$

4.- Simplification

V2 = $\frac{9786}{293}$

5.- Result

V2 = 33.4ml

3 0

3 years ago

Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles O2 to the

jek_recluse [69]

Answer:

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Explanation:

Step 1: Data given

Step 2: The balanced equation

4Fe + 3O2 → 2Fe2O3

Step 3: Calculate the mol ratio

For 3 moles O2 we'll have 4 moles Fe

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Option b says we have 2 mole Fe2O3 for each 4 moles Fe

This doesnt say anything about O2. So doesn't apply for this question.

Option C says we have 4 moles of Fe for each 2 moles Fe2O3

This is the same as option B, so doesn't apply for this question.

Option D says for each 3 moles of O2 we have 2 Fe2O3

This is true, but doesn't say anything about Fe so doesn't apply here.

4 0

3 years ago

Read 2 more answers

A team of researchers are working on a project to make a new kind of airplane fuel. During their experiment, there was an explos

tiny-mole [99]

Well for a start, this makes absolutely no sense, "discovered a fuel that burns so hot that it becomes cold."

And yes, it's not science if the experiment can't be repeated. In fact they should WANT it to be repeated so that you can get credit for discovering something new and then possibly harness this effect to produce useful applications. 

For all we know they had a fewer of LN2 in the lab that got shredded by the blast, LN2 could certainly have frozen many things (not metal though, since metal is already solid at room temperature, (except for mercury)), and afterwards would leave no trace.

6 0

3 years ago

Just need a letter so no that does not help

il63 [147K]

Like A B C D or like a mailed letter

3 0

3 years ago

What is the mass of 1.2 x 1023 atoms of arsenic?

Gre4nikov [31]

Answer:

14.93 g

Explanation:

First we convert 1.2 x 10²³ atoms of arsenic (As) into moles, using Avogadro's number:

1.2 x 10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.199 mol As

Then we can calculate the mass of 0.199 moles of arsenic, using its molar mass:

0.199 mol * 74.92 g/mol = 14.93 g

Thus, 1.2x10²³ atoms of arsenic weigh 14.93 grams.

6 0

3 years ago