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Oksana_A [137]
3 years ago
6

Find the domain and range of the relation. {(−7,−18),(−23,21),(4,13),(−17,22),(2,−10)}

Mathematics
2 answers:
Basile [38]3 years ago
7 0

Answer: Domain = all x values and Range = all y values

Step-by-step explanation:

The domain of a function is all the allowed x values that make the function true. Luckily you were already given the domain. Its all the x values.

The range of a function is pretty much all the allowed y values of a function. Or, what y values the function can be equal to. So that's just all the y values

When listing the domain and range, you generally want to do it from least to greatest and you do not want to repeat any values

frosja888 [35]3 years ago
3 0

Answer:

D:{ -23,-17,-7,2,4}

R:{-18,-10,13,21,22}

Step-by-step explanation:

The domain is the input

D:{ -7,-23,4,-17,2}

We normally put them in numerical order

D:{ -23,-17,-7,2,4}

The range is the output

R:{-18,21,13,22,-10}

We normally put them in numerical order

R:{-18,-10,13,21,22}

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Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
2 years ago
Help me with this please
KiRa [710]
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3 years ago
The sum of -5, -9, and 10 is _______.<br> A. 14<br> B. -14<br> C. 4<br> D. -4
saul85 [17]

Answer:

D. -4

Step-by-step explanation:

-5 + -9 = -14

-14 + 10 = -4

4 0
2 years ago
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If it is 4:40 now, what time was it 5 hours and 15 minutes ago?
mamaluj [8]
The answer is that it would be 11:25
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2 years ago
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the area of a triangle is 36 sq. inches. if the base of the triangle is 6 inches, what is its height? a. 15 inches b. 6 inches c
inessss [21]
A=1/2bh
b=6
a=36
36=1/2(6)(h)
36=3h
divide both sides by 3
12=h

height=12 inches

answer is D
8 0
3 years ago
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