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2 years ago

Pls solve ASAP!! Review the attachment and solve. Pls hurry!

Mathematics

1 answer:

Virty [35]2 years ago

6 0

Answer:

A. 3

Step-by-step explanation:

ΔDEC is bigger than ΔABC by 5. For the hypotenuse, 25 is 5 times bigger than 5.

So, side DE on ΔDEC has to be 5 times bigger than side AB on ΔABC.

If side AB equals 3, side DE equals 18 - 3, which is 15.

15 is five times bigger than 3, so the answer is A. 3.

Hope that helps.

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-3/v=-6 simply as much as possible

Aleksandr [31]

Hey!

In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

Original Equation :
$\frac{-3}{v} = -6$

New Equation {Added Multiply Both Sides by V} :
$\frac{-3}{v} v=-6v$

Solution {New Equation Solved} :
$-3 = -6v$

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

Old Equation :
$-3 = -6v$

New Equation {Switched} :
$-6v=-3$

Now we'll divide both sides by v to get v on its own.

Old Equation :
$-6v = -3$

New Equation {Added Divide Both Sides by V} :
$\frac{-6v}{v} = \frac{-3}{v}$

Solution {New Equation Solved} :
$v = \frac{1}{2}$

So, this means that in the equation $\frac{-3}{v} =-6$ , $v = \frac{1}{2}$ .

Hope this helps!

- Lindsey Frazier ♥

3 0

3 years ago

One bottle of shampoo cost $6 for 8 ounces. A second bottle costs $4 for 5 ounces of shampoo. Which has the lower unit rate. How

ser-zykov [4K]

The $4 for 5 ounces because think about how much 1 ounce would be so that's how you would get your answer it tells you which on is the lowest

8 0

3 years ago

A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03% chlorine. Starting at tequals0, city water conta

Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.

Remember, 1 h = 60 minutes. The initial value problem is

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x = - 6* 10⁻⁴*(3x - 10⁻¹) x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C or |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

7 0

3 years ago

Question 1: find the volume of a cube whose total surface area is 486cm^2

lapo4ka [179]

<h3>The volume of cube is 729 cubic centimeter</h3>

Solution:

The surface area of cube is given as:

$Surface\ area = 6a^2$

Where, "a" is the length of side of cube

Given that, surface area = 486 square centimeter

$486 = 6a^2\\\\a^2 = \frac{486}{6}\\\\a^2 = 81\\\\a = 9$

Find the volume of cube:

$volume\ of\ cube = a^3\\\\volume\ of\ cube = 9^3\\\\volume\ of\ cube = 9 \times 9 \times 9\\\\volume\ of\ cube = 729$

Thus volume of cube is 729 cubic centimeter

8 0

3 years ago

I need help I’m stuck on this

arsen [322]

press ask for help i think it my help im also stumped on that

8 0

2 years ago