6. A restaurant offers a lunch special in which a customer can select from one of the 7 appetizers, one of the 10 entrees, and o
ne of the 6 desserts. How many different lunch specials are possible?
Show your work
2 answers:
Answer:
the total different lunches is 420
Step-by-step explanation:
Given that:
- Number of appetizers: 7
- Number of entrees: 10
- Number of desserts: 6
As we know that, a customer can choose 3 of the above items in their lunch and it is a combination problem.
So we have:
- P(A)The possible outcome when a customer choose appetizer : 7
- P(E)The possible outcome when a customer choose entree: 10
- P(D)The possible outcome when a customer choose desert: 6
So the total different lunches is:
P(A) *P(E)*P(D)
= 7*10*6
= 420
Hope it will find you well.
Answer:
The answer is 420 lunch specials
Step-by-step explanation:
10×7=70 70×6=420
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