Question

During a takeoff run, an aircraft starts from rest and has a lift-off speed of 120 km/h. a. What minimum constant acceleration does the aircraft require if the aircraft is to be airborne after a takeoff run of 280 m?

Answer 1

Answer:

1.984 m/s^2

Explanation:

initial velocity of air craft, u = 0 m/s

final speed of the aircraft, v = 120 km/h

Convert the speed into m/s from km/h

So, v = 120 km/h = 33.33 m/s

distance, s = 280 m  

Let a be the acceleration of the aircraft.

Use third equation of motion

$v^{2}=u^{2}+2\times a\times s$

$33.33^{2}=0^{2}+2\times a\times 280$

a = 1.984 m/s^2

Thus, the acceleration of the aircraft is 1.984 m/s^2.