0.5m/s. Take the velocity of the bug and subtract from the velocity of the oncoming breeze because they are opposite. If the breeze was in the same direction that the bug was flying, then your answer would be the sum of the two.
The downwards component of weight of the object would be 35sin25 degrees = 14.8
F=14.8 - 8 = 6.8 N m= 35/9.8= 3.57 kg
F=mA
Therefore,
3.57A= 6.8 N
=> A= 6.8/3.57
=> A= 1.902 ms^-2
F(max)= (U)R where (U)= coefficient of friction
and R= Normal reaction force
R= 35cos25
= 31.72 N
Since, F(max)= 8
8= (U)* 31.72
=>(U)= 8/31.72
=>(U)= 0.25
In accordance with the definition of density as r = m/V, in order to determine the density of
matter, the mass and the volume of the sample must be known.
The determination of mass can be performed directly using a weighing instrument.
The determination of volume generally cannot be performed directly. Exceptions to this rule
include
· cases where the accuracy is not required to be very high, and
· measurements performed on geometric bodies, such as cubes, cuboids or cylinders, the volume
of which can easily be determined from dimensions such as length, height and diameter.
· The volume of a liquid can be measured in a graduated cylinder or in a pipette; the volume of
solids can be determined by immersing the sample in a cylinder filled with water and then
measuring the rise in the water level.
Because of the difficulty of determining volume with precision, especially when the sample has a
highly irregular shape, a "detour" is often taken when determining the density, by making use of the
Archimedean Principle, which describes the relation between forces (or masses), volumes and
densities of solid samples immersed in liquid:
From everyday experience, everyone is familiar with the effect that an object or body appears to
be lighter than in air – just like your own body in a swimming pool.
Figure 3: The force exerted by a body on a spring scale in air (left) and in water (right)
If they research it then they would get the answer that they need to find out of the universe that is what I think.
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Answer:
a) They are in the same point
b) t = 0 s, t = 2.27 s, t = 5.73 s
c) t = 1 s, t = 4.33 s
d) t = 2.67 s
Explanation:
Given equations are:
Constants are:
a) "Just after leaving the starting point" means that t = 0. So, if we look the equations, both 
and 
depend on t and don't have constant terms.
So both cars A and B are in the same point.
b) Firstly, they are in the same point in x = 0 at t = 0. But for generalized case, we must equalize equations and solve quadratic equation where roots will give us proper t value(s).
s, 
s
c) Since the distance isn't changing, the velocities are equal. To find velocities, we need to take the derivatives of both equations with respect to time and equalize them.
s, 
s
d) For same acceleration, we we need to take the derivatives of velocity equations with respect to time and equalize them.
s
