Answer:
- f(x) = x^3 -4x
- f(x) = -2x^3 +8x
Step-by-step explanation:
The zeros are at -2, 0, and +2, so the function will be of the form ...
f(x) = k·(x +2)(x)(x -2) . . . . . for some vertical expansion factor k
You recognize that (x+2)(x-2) is the factoring of the difference of squares, so ...
f(x) = k·x·(x^2 -4)
If we let x=1, we get
f(1) = k·(1)(1 -4) = -3k
For the first graph, it looks like we have ...
f(1) = -3 = -3k . . . . so, k = 1
For the second graph, it looks like we have ...
f(1) = 6 = -3k . . . . so, k = -2
_____
In standard form, the first graph is described by ...
f(x) = 1·x·(x^2 -4) = x^3 -4x
The second graph is described by ...
f(x) = -2x·(x^2 -4) = -2x^3 +8x
I believe that the answer is 7/4 or 6:1
Do you mean to the nearest ten? If so, then it would be 60. Look to the right of the number you are to round, if it's 5 or more then round up. If it's 4 or less then round down. If it's a zero, then do nothing. The numbers following the one you are rounding get changed to zero's.
Answer:
Well, one penny adds up quickly. In a year, you can save nearly £700 by putting just 1p away in day one, 2p in day two….you get the idea. For a normal (365 day) year you can save £667.95, and in a leap year you can save £671.61.
Step-by-step explanation:
Answer:
6 hrs.
Step-by-step explanation:
So 391.00 can just be converted to 391 because they mean the same thing, so since we have $391 for 23 hrs, we can divde those, which gives us 17, this answer would show that Ethan earns $17 a hour, so if we divide how much he earns by the hour by how much money he could earn by next week ( 102/17), that would give us 6, Therefore, Ethan would need to work 6 hours for $102.00