Newton's 2nd law of motion:
Force = (mass) x (acceleration)
= (0.314 kg) x (164 m/s²)
= 51.5 newtons
(about 11.6 pounds) .
Notice that the ball is only accelerating while it's in contact with the racket.
The instant the ball loses contact with the racket, it stops accelerating, and
sails off in a straight line at whatever speed it had when it left the strings.
Answer:
P = 2 pi R / v period of space station
F / m = v^2 / R centripetal force per unit of mass
So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2
Also, F / m = 9.8 m/s^2 earth's gravitational attraction
So 9.8 = 4 pi^2 R / P^2 or R = 9.8 P^2 / 4 * pi^2) = 195 m
Or D = 2 R = 390 m the diameter required
Answer:
W of the person in moon ≈ 124.70 N
Explanation:
Weight: Weight of a body can be defined as the product of mass and the gravitational acceleration of the body. The S.I unit of weight is Newton (N). It can be expressed mathematically as
W = mg
Where W = weight of the body, m = mass of the body (kg) and a = acceleration of the body (m/s²)
Weight(W) = Mass (m) × Acceleration due to gravity (g)
∴ W = m × g.
If the person is on the moon,
Mass = 76.5 kg.
g (moon) = 16.6% of g ( earth)
But g(earth) = 9.80 m/s².
∴ g (moon) = 9.80 × (16.6/100)
g (moon) = 1.63 m/s², m = 76.5 Kg
∴ Weight of the person in moon = 76.5 × 1.63 =124.695 N
W of the person in moon ≈ 124.70 N
Radium........ Hope this helps :)
Its 1.73793151243 as a whole but if rounded it is 1.74
