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allochka39001 [22]

3 years ago

10

The period of a sound wave is 0.002 seconds. The speed of a sound is 344 m/s. Find the frequency and wavelength of the sound wav

e.

1 answer:

ankoles [38]3 years ago

5 0

Answer:

I think that's the solution

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Describe the relationship between kinetic energy and speed and give an example of how changing and object speed would affect its

Andreas93 [3]

Answer:

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Explanation:

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3 years ago

Balboa Park in San Diego has an outdoor organ. When the air temperature increases, the fundamental frequency of one of the organ

musickatia [10]

The fundamental frequency of one of the organ pipes will go up or increase.

When pressured air is forced into an organ pipe, it echoes at a particular pitch, generating the sound of the pipe organ. Each pipe has been adjusted to a particular pitch on the musical scale.

A musical instrument called an outdoor pipe organ is used to perform music. It produces some calming tones and has a really serene sound. The organ pipe produces the sound of the outdoor organ. The wavelength of the sound is also dependent on the length of the pipe. The fundamental frequency of one of the organ pipes will grow as the speed of the sound increases as the ambient air temperature rises.

The correct option is (c).

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1 year ago

Initial velocity=3m/s, final velocity=5m/s, displacement=2m. Find the acceleration.

shusha [124]

Answer:

Explanation:

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4 0

3 years ago

Read 2 more answers

I Need answer ASAP

anzhelika [568]

Answer: Convection and conduction

Tell me that I got it right??

Explanation

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3 years ago

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A water tower is a familiar sight in many towns. The purpose of such a tower is to provide storage capacity and to provide suffi

Mademuasel [1]

The image of the water tower and the houses is in the attachment.

Answer: (a) P = 245kPa;

(b) P = 173.5 kPa

Explanation: <u>Gauge</u> <u>pressure</u> is the pressure relative to the atmospheric pressure and it is only dependent of the height of the liquid in the container.

The pressure is calculated as: P = hρg

where

ρ is the density of the liquid, in this case, water, which is ρ = 1000kg/m³;

When it is full the reservoir contains 5.25×10⁵ kg. So, knowing the density, you know the volume:

ρ = $\frac{m}{V}$

V = ρ/m

V = $\frac{5.25.10^{5}}{10^{3}}$

V = 525 m³

To know the height of the spherical reservoir, its diameter is needed and to determine it, find the radius:

V = $\frac{4}{3}.\pi.r^{3}$

$r = \sqrt[3]{ \frac{3}{4\pi } .V}$

r = $\sqrt[3]{\frac{525.3}{4\pi } }$

r = 5.005 m

diameter = 2*r = 10.01m

(a) Height for House A:

h = 15 + 10.01

h = 25.01

P = hρg

P = 25.01.10³.9.8

P = 245.10³ Pa or 245kPa

(b) h = 25 - 7.3

h = 17.71

P = hρg

P = 17.71.1000.9.8

P = 173.5.10³ Pa or 173.5 kPa

4 0

3 years ago