The distance covered is simply the length of the entire trip, which is 12m + 16m, or 28m.
The displacement is the distance from the starting point to the ending point along with the direction of the net motion. The dog walks 12m east then 16m west, so its resultant displacement is 4m west.
Answer:
The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.
Answer:
The funda mental frequency of the original tube is 182Hz.
Explanation:
See the attachment for the calculation steps.
In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.
For closed tubes
f = nv/4L (n = 1, 3, 5,...n)
f = nv/2L (n = 1, 2, 3,...n)
The details of calculation can be found below in the attachment.
Answer:
54 km/h
Explanation:
given,
speed of the biker = 36 Km/h
time = 10 s
acceleration = 0.5 m/s²
speed at which it crosses the finish line = ?
v = 36 x 0.278 = 10 m/s
using equation of motion
v = u + a t
v = 10 + 0.5 x 10
v = 15 m/s
v = 15 x 3.6 = 54 km/hr
speed at which the biker crosses the finish line is equal to 54 km/h
