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Two point charges, feel a force of 1. 0 n when they are 2. 0 cm apart. if they are moved further apart to 8. 0 cm. The electric force between them will be F2 = 1/16 J
A charged particle, also called an ion, is an atom with a positive or negative charge. This happens whenever something called an ionic bond forms. Two particles that have different numbers of electrons (the smallest particle in an atom which is negative) start reacting to each other.
According to Coulomb's law, the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. It acts along the line joining the two charges considered to be point charges.
F1 = K q1*q2 /
1 = K q1*q2 /
F2 = K q1*q2 /
F2 = K q1*q2 /
F1 / F2 = 64 / 4
1 / F2 = 16 / 1
F2 = 1/16 J
To learn more about Coulomb's law here
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Explanation:
Well let see, we don't have any information about the initial distance we have to use our logic
assuming that the distance moves from 1 to 2 m with initial speed , it means that the distance factor is 2
Since the initial speed has doubled, it would be very likely that the factor of the distance is MORE THAN 2 . Find the answer that either got 3 or 4 distance factor
hope this helps