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Salsk061 [2.6K]
3 years ago
8

An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir

cuit that "clicks" in response to current. The faster the current, the more clicks per minute. In this experiment, the number of clicks in one minute is recorded for each color of light shining on the photocell. To change the color of light, a different color of cellophane is placed over the same flashlight and the flashlight is then located a specific distance from the photocell.
1. Which of the following was not kept constant?
the test for photocell activation
the color of the light after it has passed through the cellophane
the distance of the light from the photocell
the source of the original light

2. In the above experiment, which factor is the independent variable?
the photocell
the color of the light
the number of clicks
the original source of the light

3. Which of the following would be the best hypothesis for this experiment?
Photoelectric cells are affected by different wavelengths of light.
Red light will activate the photocell to the highest degree.
If photoelectric cells respond better to short wavelengths of light, the red light should activate it the least and blue the most.
Physics
2 answers:
Stels [109]3 years ago
5 0
..................”...........
barxatty [35]3 years ago
3 0

Answer:

1. The color of the light after it has passed through the Cellophane

2. The color of the light

3. If photoelectric cells respond better to short wavelengths of light, the red light should activate it the least and the blue the most.

Explanation:

1. The color of the light changes depending on what color cellophane is put in front of the flashlight

2. The color of the light is the independent variable because it is the only part of the experiment that is being altered.

3. In the description they say the purpose of the experiment is to determine what color of light will have the largest affect on the photoelectric cell. Therefore, this matches up best. The one where is says Photoelectric cells are affected by different wavelengths of light doesn't mention which one is better just that they are affected.

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allochka39001 [22]

Options (b) and (d) are correct about an electric motor.

An electric motor is a device which coverts electrical energy into mechanical energy.It works on the principle that when a current carrying coil is placed in a magnetic field, it experiences torque. Because of that torque, the coil rotates and thus the electrical energy gets converted into mechanical (motion) energy.

7 0
3 years ago
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Can someone help me a bit on this? Will mark brainliest. ( no physical science option soooo)
Advocard [28]

Answer:

When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.

The corresponding relation for diffraction is

d sin(\theta) \approx \lambda,

where \lambda is the wavelength of light, d is the slit width, and \theta is the diffraction angle.

From this relation we clearly see that the diffraction angle \theta is directly proportional to the wavelength  \lambda of light—longer the wavelength larger the diffraction angle.

7 0
3 years ago
a body of radius R and mass m is rolling horizontally without slipping with speed v. it then rolls us a hill to a maximum height
ki77a [65]

Answer:

mR²/2

Explanation:

Here is the complete question

An object of radius′

R′  and mass ′

M′  is rolling horizontally without slipping with speed ′

V′

. It then rolls up the hill to a maximum height h = 3v²/4g. The moment of inertia of the object is (g= acceleration due to gravity)

Solution

Since it rolls without slipping, there is no friction. So, its initial mechanical energy at the horizontal surface equals its final mechanical energy at the top of the hill.

Since the object is rolling initially, and on horizontal ground, it initial energy is kinetic and made up of rotational and translational kinetic energy.

So, E = K + K'

E = 1/2mv² + 1/2Iω² where m = mass of object, v = speed of object, I = moment of inertia of object and ω = angular speed of object = v/r where v = speed of object and R = radius of object.

Also, the final mechanical energy of the object, E' is its potential energy at the top of the hill. So, E' = mgh.

Since E = E',

1/2mv² + 1/2Iω² = mgh

substituting the values of ω and h into the equation, we have

1/2mv² + 1/2Iω² = mgh

1/2mv² + 1/2I(v/R)²= mg(3v²/4g)

Expanding the brackets, we have

1/2mv² + 1/2Iv²/R²= 3mv²/4

Dividing through by v², we have

1/2m + I/2R²= 3m/4

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I/2R² = 3m/4 - m/2

Simplifying, we have

I/2R² = m/4

Multiplying through by 2R², we have

I = m/4 × 2R²

I = mR²/2

6 0
2 years ago
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Alika [10]

Answer:

See Explanation

Explanation:

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