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3 years ago

6

Use the law of sines to solve the triangle, if two solutions exist, find both. A= 58 a=11.4 b=12.8

1 answer:

ch4aika [34]3 years ago

5 0

Answer:

B=80.71 ,C=41.29,c=8.56

Step-by-step explanation:

Based on Law of sines solution is given the photo

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2 years ago

The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.

taurus [48]

Answer:

$A\approx 28^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that area of triangle ABC is 3√2 square inches.

$\text{Area}=\frac{1}{2}\text{Base}\times \text{height}$

We know that area of triangle an be found using trigonometry as:

$\text{Area}=\frac{1}{2}\times c\times h$

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$3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)$

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Now, we will use inverse sine to find the value of angle A as:

$A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})$

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3 years ago