Short answer
For 6: 72 ft^2
For 7: 650 m^2
Six
The base is a square. It's measurement is s = 4
Base = 4^2
Base = 16 ft^2
One triangle
A = 1/2 * b * h
A = 1/2 * 4 * 7
A = 14 tt^2
Four triangles
A = 4 * 14
A = 56 ft^2
Total Area = 56 + 16 = 72 ft^2
Answer 72 square feet
Seven
Triangles
Area of 1 triangle = 1/2 * 10 * 13
Area of 1 triangle = 65
Area of 6 triangles
Area of 6 triangles = 6 * area of 1 triangle
Area of 6 triangles = 390
Base
As near as I can tell, the base is a hexagon. It's using a rather out of the way method of drawing it. I will assume it is a regular hexagon. The area of a regular hexagon is 3 sqrt(3)/2 * S^2 where s is the side of the hexagon.
Area = 3sqrt(3)/2 s^2
s = 10
Area = 3sqrt(3)/2 10^2
Area = 5.1962 * 100 /2
Area = 259.81
Total area
Total area = area of the base + area of the triangles
Total area = 259.81 + 390
Total area (rounded ) = 650
Answer C <<<< answer
I'll do one more in this batch and then you'll need to repost again.
Eight
If you draw two diagonals on the base of the figure, the intersection point will meet the base of the height. Read that a couple of times.
Join the intersection to the midpoint of the length of the square bottom. You should get 3.5
x is found by using the pythagorean theorem.
h = 6
s = 3.5
x = ????
x^2 = 6^2 + 3.5^2
x^2 = 36 + 12.25
x^2 = 48.25
x = sqrt(48.25)
x = 6.95
C <<<< answer
Answer:
(3 and 15)
Step-by-step explanation:
If the product of both of these two numbers needs to be a negative 45 then there are no pair of integers that comply with both requirements.
If the multiplication in the question is wrong and it is a positive 45 then the pair of integers that would comply with these requirements would be (3 and 15). Multiplying this pair together would give you 45 and the difference between them is also 12 meaning it complies with both requirements that were asked for in the question.
Answer: k ≤ -4 or k ≥ 
<u>Explanation:</u>
| 3k + 4 | ≥ 8
3k + 4 ≥ 8 or 3k + 4 ≤ -8
<u> -4</u> <u> -4 </u> <u> -4</u> <u>-4 </u>
3k ≥ 4 or 3k ≤ -12
<u>÷3 </u> <u>÷3 </u> <u> ÷3 </u> <u>÷3 </u>
k ≥ or k ≤ -4
just do it like nike said
