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Crazy boy [7]
3 years ago
6

Use the law of sines to solve the triangle, if two solutions exist, find both. A= 58 a=11.4 b=12.8

Mathematics
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

B=80.71 ,C=41.29,c=8.56

Step-by-step explanation:

Based on  Law of sines solution is given the photo

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The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.
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Answer:

A\approx 28^{\circ}

Step-by-step explanation:

Please find the attachment.  

We have been given that area of triangle ABC is 3√2 square inches.

\text{Area}=\frac{1}{2}\text{Base}\times \text{height}

We know that area of triangle an be found using trigonometry as:

\text{Area}=\frac{1}{2}\times c\times h

\text{sin}(A)=\frac{h}{9}\\h=9\cdot \text{sin}(A)

3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)

3\sqrt{2}=9\cdot \text{sin}(A)

9\cdot \text{sin}(A)=3\sqrt{2}

\text{sin}(A)=\frac{3\sqrt{2}}{9}

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Now, we will use inverse sine to find the value of angle A as:

A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})

A=28.1255057^{\circ}

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Therefore, the measure of angle A is approximately 28 degrees.

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How do properties of integer exponents help you write equivalent expressions
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