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professor190 [17]
3 years ago
10

Write the function shown on the graph

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0

Answer: g(x)=|x|+3

Step-by-step explanation:

By definition, the Absolute Value parent function has the following form:

f(x)=|x|

The vertex of the graph is at the point (0,0)

It is important to remember the following transformations for a function:

If f(x)+k, then the function is shifted "k" units up.

If f(x)-k, then the function is shifted "k" units down.

If f(x+k), then the function is shifted "k" units left.

If f(x-k), then the function is shifted "k" units right.

Let be g(x) the function shown in the graph provided in the exercise.

You can observe that its Vertex is at the point (0,3).

Therefore, you can conclude that the function g(x) is obtained by shifting the Absolute Value parent function 3 units up.

Then, this is:

g(x)=|x|+3

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harkovskaia [24]

Answer:

D) x=9 ; y=3√(3)

Step-by-step explanation:

Sin(30)=\cfrac{y}{6\sqrt{3} }

\cfrac{18y}{6\sqrt{3}}=18\sin \left(30^{\circ \:}\right)

\sqrt{3}y=9

\cfrac{\sqrt{3}y}{\sqrt{3}}=\cfrac{9}{\sqrt{3}}

y=3\sqrt{3}

~

Cos(30)=\cfrac{x}{6\sqrt{3} }

\cfrac{18x}{6\sqrt{3}}=18\cos \left(30^{\circ \:}\right)

\sqrt{3}x=9\sqrt{3}

\cfrac{\sqrt{3}x}{\sqrt{3}}=\cfrac{9\sqrt{3}}{\sqrt{3}}

x=9

Therefore, x=9 and y=3√(3)

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8 0
2 years ago
Prove that, in a right triangle with a 15° angle, the altitude to the hypotenuse is one fourth of the hypotenuse.
igomit [66]

Consider the attached figure. If AB has length 1, then BC has length sin(15°) and CD (the altitude of triangle ABC) has length sin(15°)·cos(15°).

By the double angle formula for sin(α), ...

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Rearranging, this gives

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We have

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... CD = sin(30°)/2 = (1/2)/2 = 1/4

That is, the altitude, CD, is 1/4 the hypotenuse, AB, of triangle ABC.

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alexgriva [62]

Answer:

OPTION A: $ \frac{12}{1 + 8x} $, where $ x \ne - \frac{1}{8} $.

Step-by-step explanation:

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Taking $ x^4 $ common outside in the denominator, we get:

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$ x^4 $ will get cancelled on the numerator and denominator, we get:

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we know that the denominator can not be zero.

That means, 1 + 8x $ \ne $ 0.

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So, the answer is: $ \frac{-12}{1 + 8x} $, where $ x \ne \frac{-1}{8} $.

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