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Thepotemich [5.8K]
3 years ago
11

Two hikers are 14 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walk

s 2.8 mph faster than the other.
Physics
2 answers:
ELEN [110]3 years ago
5 0

Answer:

df

Explanation:

Elza [17]3 years ago
3 0

Answer:

The rate of one is 2.1 mph and the rate of the other is 4.9 mph

Explanation:

Let the rate of one be y mph

The rate of the other = (y+2.8) mph

Total rate = y + y + 2.8 = (2y+2.8) mph

Total rate = distance apart/time

2y + 2.8 = 14/2

2y + 2.8 = 7

2y = 7 - 2.8

2y = 4.2

y = 4.2/2 = 2.1 mph

The rate of the other is y+2.8 = 2.1+2.8 = 4.9 mph

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Current passes through a solution of sodium chloride. In 1.00 s , 2.68× 10 16 Na + ions arrive at the negative electrode and 3.9
Lady bird [3.3K]

Answer

a) charge of the sodium ion is,

q = n e

q = 2.68 x 10¹⁶ x 1.6 x 10⁻¹⁹

q = 4.288 x 10⁻³ C

charge of the chlorine ion is,

q' = n e

q' = 3.92 x 10¹⁶ x 1.6 x 10⁻¹⁹

q' = 6.272 x 10⁻³ C

the current

i = \dfrac{q}{t} + \dfrac{q'}{t}

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3 years ago
A boat with a mass of 1000 kg drifts with the current down a straight section of river parallel to the +x+x axis with a speed of
IrinaK [193]

Answer:

A.

Explanation:

Our values are defined by,

m=1000kg\\v = 2m/s\\a = 2.7 \angle 45\°

We can express also in a vectorial way, then

v=2\hat{i} \rightarrowno values in \hat{j}

Acceleration as follow,

a= 2.7cos45 \hat{i} + 2.7 sin45 \hat{j}

We know that velocity is given by,

V(t) = v_0+at \rightarrow v_0 = 2

We need to calculate for t=3, then

v(3) = 2\hat{i} +(2.7cos45 \hat{i} + 2.7 sin45 \hat{j})*3

v(3) = (2\hat{i}+3*2.7cos45 \hat{i})+(3*2.7 sin45 \hat{j})

v(3) = (2+3*2.7cos45)\hat{i}+(5.7 sin45 )\hat{j}

v(3) = 7.7\hat{i}+5.7\hat{j}

Our mass is 1000Kg, so the momentum is

P = mv

P= 1000(7.7\hat{i}+5.7\hat{j})

P=7700\hat{i}+5700\hat{j}

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