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Sergio [31]
3 years ago
14

A person is walking down the street maintain the same speed and direction. The person is accelerating.

Physics
1 answer:
balandron [24]3 years ago
6 0

Answer:

no change in speed, therefore the body cannot be accelerated.  a=0

Explanation:

When a person is accelerating his speed must change, if the speed is in the same direction as the acceleration the speed increases and if the acceleration is in the opposite direction to the speed it decreases.

In this case there is no change in speed, therefore the body cannot be accelerated.

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The high-speed winds around a tornado can drive projectiles into trees, building walls, and even metal traffic signs. In a labor
Travka [436]

Answer:

F  = 183.153 N

Explanation:

given,

mass of the toothpick = 0.12 g = 0.00012 kg  

initial velocity = 227 m/s    

final velocity = 0 m/s      

penetration depth = 16 mm = 0.016 m        

using the equation of motion        

v² - u² = 2 a s                            

0 - u² = 2 a s                                      

- 221² = 2 × a × 0.016      

a = 1526281.25 m/s²            

Force is equal to            

F = m a

  = 0.00012 × 1526281.25

F  = 183.153 N

3 0
3 years ago
What are the variables of Boyle's law?
vesna_86 [32]

Answer: pressure and volume

Explanation:

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure of the gas provided temperature is kept constant.

Mathematically, Boyle's law can be explained as: PV = k,

where P is pressure

V is volume, and

k is a constant.

So, increase in the pressure of a gas leads to decrease in its volume and vice versa.

3 0
3 years ago
A stone is dropped off a cliff. After this stone has traveled a distance d . A second stone is dropped. the distance between the
Sladkaya [172]

Answer:

the same stones distance will be condtant .

so option no E

7 0
3 years ago
Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250
m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = \dfrac{\pi}{4}d^2

v = Terminal velocity = v=210\ m/s

s = Displacement = 150 m

a=\dfrac{v^2-u^2}{2s}

Force is given by

F = ma

F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622

The drag coefficient is 0.363999909622 (ignoring negative sign)

4 0
3 years ago
A van has a weight of 4000 lb and center of gravity at Gv. It carries a fixed 900 lb load which has a center of gravity at Gl. I
natulia [17]

Answer:

 x = 25 / μ     [ ft]

Explanation:

To solve this exercise we can use Newton's second law.

Let's set a reference system where the x axis is parallel to the road

Y axis  

       N_B + N_A - W_van - W_load = 0

       N_B + N_A = W_van + W_load

X axis

     fr = ma

     a = fr / m

the total mass is

        m = (W_van + W_load) / g

the friction force has the expression

      fr = μ N_{total}

      fr = μy (W_van + W_load)

we substitute

      a = μ (W_van + W_load)    \frac{g}{W_van + W_load}

      a = μ g

taking the acceleration let's use the kinematic relations where the final velocity is zero

       v² = v₀² - 2 a x

       0 = v₀² -2a x

        x = \frac{v_o^2}{2a}

        x = \frac{v_o^2}{2 \mu g}

        x = \frac{40^2}{2 \ 32 \  \mu}

        x = 25 / μ     [ ft]

5 0
3 years ago
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