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sertanlavr [38]
2 years ago
13

If the 5 digit number 1732p is divisible by 9, then p = O 3 O 5 O 7 O 4

Mathematics
1 answer:
OlgaM077 [116]2 years ago
8 0

Answer:

p = 5

Step-by-step explanation:

1732(5)/9 = 1925

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Help me asap
laila [671]

Answer:

C. 3a is correct.

Step-by-step explanation:

7 0
2 years ago
What is the answer to -4/3p -2/5
kaheart [24]

Answer:

Step-by-step explanation:

This expression consists of two fractions that have no common denominator but do have -2 as a common factor in the numerators.

Factoring out the -2, we get:

-2(2p/3 + 1/5)

If you want to go further, we can determine the LCD (which is 15) and then combine the fractions within parentheses:

-2(10p/15 + 3/15)

We could now factor out the 1/15 in each fraction:

-2

---- (10p + 3)

15

5 0
3 years ago
Find the volume of a sphere with a diameter of 20 inches
trasher [3.6K]

Answer:

V≈4188.79in³    

Step-by-step explanation:

4.188.79in3

7 0
2 years ago
a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum
FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The sample has 20 pills, hence n = 20.
  • 100 - 4 = 96% are acceptable, hence p = 0.96

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0

P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0

P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0

P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0

P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0
2 years ago
What sets does radical 12 belong to
adoni [48]

Step-by-step explanation: The square root of 12 is represented in the radical form as √12 which is equal to 2√3. Since, 2√3 cannot be further simplified, hence such roots are called surds.

3 0
2 years ago
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