Answer:
66+24
Step-by-step explanation:
you just have to add them
a. n-(n - 1) = 1
b. n( n - 1) = n² - n
c. (n - 1) + n = 2n - 1
d. (n - 1) + n = 2n - 1
<h3>Solution:</h3>
General Rule for Equation Solving
- Remove parentheses and combine like terms to simplify each side of the equation.
- To isolate the variable term on one side of the equation, use addition or subtraction.
- To find the variable, use multiplication or division.
Given two consecutive numbers , (n - 1) , n
simplifying :
n - (n - 1)
= n -1(n - 1)
= n - n + 1
= 1
multiplying :
n( n -1)
= n² - n
simplifying :
(n-1) + n
= n - 1 + n
= 2n -1
by adding two numbers :
(n - 1) + n
= n -1 + n
= 2n - 1
To learn more about equations refer to :
brainly.com/question/22688504
#SPJ13
The graph will be as shown in attached figure
Just need to find out under early to add graduate and undergraduate together and then see if how much out of the total of those who registered early is undergraduate
Answer: the height in inches, of the pile after 3 weeks is 34 11/12 inches
Step-by-step explanation:
Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inches. Converting 8 7/12 inches to improper fraction, it becomes 103/12 inches. The height is increasing in an arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = 17 3/4= 71/4 inches
d = 103/12 inches
n = 3 weeks
the height in inches, of the pile after 3 weeks, T3. Therefore,
T3 = 71/4 + (3 - 1)103/12
T3 = 71/4 + 2 × 103/12 = 71/4 + 103/6
T3 = 419/12 inches = 34 11/12 inches
