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3 years ago

How many numbers are 10 units from 0 on the number line? Type your answer as a numeral.

Mathematics

1 answer:

Slav-nsk [51]3 years ago

4 0

<span>Two numbers, +10 and -10, are 10 units from 0 on the number line</span>

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Type an equation for the

yawa3891 [41]

Answer:

Does the answer help you?

please mark this question as brainliest answer.Cause it take a few mins to solve your question.Tq

5 0

3 years ago

Suppose you can somehow choose two people at random who took the SAT in 2014. A reminder that scores were Normally distributed w

Sindrei [870]

Answer:

22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1497, \sigma = 322$

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1520 - 1497}{322}$

$Z = 0.07$

$Z = 0.07$ has a pvalue of 0.5279

1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

What is the probability that both of them scored above a 1520?

Each students has a 0.4721 probability of scoring above 1520. So

$P = 0.4721*0.4721 = 0.2229$

22.29% probability that both of them scored above a 1520

8 0

3 years ago

Irene is N years old. If Tom is twice as old, which of the following algebraic statements shows h

aleksley [76]

Answer:

1. 2n

Step-by-step explanation:

5 0

3 years ago

Construct the 95% confidence interval for the population mean using the appropriate distributions. a. A random sample of 50 peop

SSSSS [86.1K]

Answer: 95% confidence interval would be (26.01,29.39).

Step-by-step explanation:

Since we have given that

n = 50

Mean = 27.7

Standard deviation = 6.12

We need to construct 95% confidence interval for the population.

so, z = 1.96

So, it becomes,

$\bar{x}\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=27.7\pm 1.96\times \dfrac{6.12}{\sqrt{50}}\\\\=27.7 \pm 1.69\\\\=(27.7-1.69,27.7+1.69)\\\\=(26.01,29.39)$

Hence, 95% confidence interval would be (26.01,29.39).

4 0

3 years ago

The numbers 1 through 50 are written with red marker on slips of paper while the numbers 51 through 100 are written with blue ma

Marizza181 [45]

Given:
1 - 50 written in red marker
51 - 100 written in blue marker

Probability of selecting a number greater than 81; 100 - 81 = 19 possible numbers. 1 draw. 1/19

Probability of selecting a number written in red: 1/50

Probability of selecting a number written in blue: 1/50

Probability of selecting a number that is a multiple of 10. There are 10 instances; 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 ; 1/10

5 0

3 years ago