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Karo-lina-s [1.5K]
4 years ago
8

Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022

kg, respectively. The average distance separating the Earth and the moon is 3.83 x 108 m.
Physics
1 answer:
Neporo4naja [7]4 years ago
3 0

Answer:

F =1.974 \times {10}^{ 20}  N

Explanation:

The formula for the force of attraction is given by

F = \frac{Gm_1m_2}{ {r}^{2} }

where,

F= Force

G= universal gravitational constant

m_1 and \: m_2

are the masses of the two bodies.

r= the distance between the two bodies.

Let the mass of the Earth=m_1 and that of the moon= m_2.

From the question,

m_1= 5.98\times {10}^{24}  kg

m_2= 7.26 \times {10}^{22}  kg,

r= 3.83 \times10^8  m

We substitute these values into the equation,Assuming,

G = 6.67 \times {10}^{ - 11} N m^2 kg^{-2}

This implies that,

F =  \frac{6.67 \times {10}^{ - 11 } \times 5.98 \times  {10}^{24} \times 7.26 \times  {10}^{22}}{ ({3.83 \times 10}^{8})^2}

F = 1.974 \times {10}^{20} N

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WITCHER [35]

Answer:

7.0s

Explanation:

Mass = 0.41kg

F= 81N

t = 0.22s

¤ = 29°

Lo = 86m

From impulse equation,

F*t = m* v

81 * 0.22 = 0.41 * v

Vo = 17.82 / 0.41

Vo = 43.46m/s

Vx= velocity across horizontal plane

Vy = velocity across vertical plane

Vx = Vo * cos ¤

Vy = Vo * sin ¤

Vx = 43.46 * cos 30° = 37.64 m/s

Vy = 43.46 sin 30° = 21.73 m/s

Distance travelled across the vertical plane,

L = Lo + Vy *t + ½gt²

0 = 86 + 21.73t - 4.9t²

4.9t² - 21.73t - 86 = 0

Solving for t in the quadratic equation,

t = 6.96 or -10.04

Using the positive root since time can't be negative, t = 6.96 approximately 7.0s

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A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?
Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

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A mass of 2000 kg is raised 5.0 m in 10 seconds what is the potential energy of the mass at this height?
kvv77 [185]

Answer:

A. 98,000 J

Explanation:

The gravitational potential energy of an object is given by

U = mgh

where

m is the mass of the object

g is the gravitational acceleration

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In this problem,

m = 2000 kg

g = 9.8 m/s^2

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