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sveta [45]
2 years ago
7

A sound wave has a frequency of 265 hz and a wavelength measured at 1.3

Physics
1 answer:
pochemuha2 years ago
8 0

Answer:

V = f λ     speed of wave in terms of frequency and wavelength

t = S / V      time for wave to travel a distance S

t = 91.4 m / 344.5 m/s = .265 sec        time to travel 91.4 m

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larisa [96]

Answer:

I believe thermal energy is a type of kinetic energy because the atoms are vibrating. Correct me if I am wrong.

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3 years ago
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Four point charges are located at the corners of a square. Each charge has magnitude 4.50 nC and the square has sides of length
Dafna11 [192]

Answer:

Explanation:

r^2 = [\frac{l}{2}]^2 +[\frac{l}{2}]^2

r^2 = \frac{2l^2}{4}

r^2 =  \frac{l^2}{2}

we know that electric field is given as

E = \frac{kq}{r^2}

from the figure electric field c and electric field a CANCEL OUT EACH OTHER

so, we have E_B and E_D is toward -q direction

E_{net} = 2E = 2* \frac{kq}{r^2} =  \frac{2kq}{r^2}

E_{net} =\frac{2kq}{(\frac{l}{2})^2}

E_{net} =\frac{4kq}{l^2}

E_{net} = \frac{4*9*10^{9} *3.2*10^{-9}}{(2*10^{-2})^2}

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3 0
4 years ago
A bar magnet is placed on a table so that the north pole faces right.
Katena32 [7]

The correct answer is C. They are pointing right to left.


Explanation.

A magnet has two poles, a north pole and a south pole.  When dealing with magnets, we define the concept of a magnetic field. A magnetic field represents the effect of the magnet on magnetic materials and moving charges in the space around the magnet. For every magnet, the magnetic field lines always point away from the north pole of the magnet towards the south pole. Since the north pole of this magnet faces right, the magnetic field lines point towards the left.

The correct answer is C. They are pointing right to left.

5 0
4 years ago
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A circular loop of radius 11.9 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane
djverab [1.8K]

Answer:

(a). The strength of the magnetic field is 0.1933 T.

(b). The magnetic flux through the loop is zero.

Explanation:

Given that,

Radius = 11.9 cm

Magnetic flux \phi=8.60\times10^{-3}\ T m^2

(a). We need to calculate the strength of the magnetic field

Using formula of magnetic flux

\phi=BA\cos\theta

\phi=BA\cos0

\phi=BA

B=\dfrac{\phi}{A}

B=\dfrac{\phi}{\pi r^2}

Put the value into the formula

B=\dfrac{8.60\times10^{-3}}{\pi\times(11.9\times10^{-2})^2}

B=0.1933\ T

(b). If the magnetic field is directed parallel to the plane of the loop,

We need to calculate the magnetic flux through the loop

Using formula of flux

\phi=BA\cos\theta

Here, \theta=90^{\circ}

\phi=BA\cos90

\phi=0

Hence, (a). The strength of the magnetic field is 0.1933 T.

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3 years ago
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In subduction, _____.
user100 [1]

The answer is the less dense plate slides over the denser plate.

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