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harkovskaia [24]
2 years ago
5

A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?

Physics
1 answer:
Kobotan [32]2 years ago
5 0

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

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Answer:

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Answer:

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Explanation:

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The minus sign means that the acceleration due to gravity is always downward, so if we assume that the positive direction is upwards it must be negative.

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v= v₀ -g((v₀/g)-0.7 s) = v₀ - v₀ + g*0.7 s

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⇒ v = 6.86 m/s

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