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Reika [66]
3 years ago
6

Can't figure out the slope and y-intercept

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0

Answer:

Let's start by finding the x- and y-intercepts. On this graph, the x-intercept (the point where the line intersects the x-axis) is (6, 0). The y-intercept (the point where the line crosses the y-axis) is (0, 4).

With those two points, we can determine the slope. Slope, in simple terms, is the change in y value divided by the change in x value between any two points on the line. Stated mathematically, if you have a point with coordinates (x₁, y₁) and another point with coordinates (x₂, y₂) on the same line, then the slope of the line can be calculated as:

slope = (y₁ - y₂)/(x₁ - x₂)

We already have points (6, 0) and (0, 4), so let's use those.

x₁ = 6

y₁ = 0

x₂ = 0

y₂ = 4

slope = (0 - 4)/(6 - 0) = -4/6 = -2/3

Slope-intercept form is always written as y = mx + b where m is the slope of the line and b is the y-value of the y-intercept. We know that the slope (m) is -2/3 and the y-value of the y-intercept (b) is 4, so the line can be written in slope-intercept form as:

y = (-2/3)x + 4

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Step-by-step explanation:

Ok, when we have a function y = f(x)

> A reflection over the x-axis changes a point (x, y) to a point (x, -y), then for a function (x , y = f(x)) the point will change to (x, -y =- f(x))

then for a funtion g(x), this tranformation can be written as h(x) = -g(x).

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Step-by-step explanation:

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