So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
Answer:
False
Explanation:
When electrons move from lower to higher electron energy level they absorb the energy. When they move from higher to lower energy level they emit energy.
Carbohydrates, proteins, lipids, and Nucleic Acids.
Answer:
The molarity of the solution is 1, 23 M.
Explanation:
We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)
Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g
58, 5 g-----1 mol NaCl
89,94 g ---------x= (89,94 g x 1 mol NaCl)/58, 5 g= 1,54 mol NaCl
1249 ml solution------ 1,54 mol NaCl
1000ml solution------x= (1000ml solutionx 1,54 mol NaCl)/1249 ml solution
x=1,23 mol NaCl---> The solution is 1, 23 molar (1,23 M)
In the physical properties, it is mentioned that the element has 4 valence electrons. The elements in the periodic table are arranged such that, the number of valence electrons present in the neutral atoms belonging to a particular group is equal to the group number.
Thus, the unidentified element can be best classified as a nonmetal in period 4
Ans C)