$\bf \sqrt{75x^5y^8}\qquad 
\begin{cases}
75=3\cdot 25\\
\qquad 3\cdot 5^2\\
x^5=x^{4+1}\\
\qquad x^4x^1\\
\qquad (x^2)^2x\\
y^8=y^{4\cdot 2}\\
\qquad (y^4)^2
\end{cases}\implies \sqrt{3\cdot 5^2\cdot (x^2)^2x(y^4)^2}
\\\\\\
5x^2y^4\sqrt{3x}$

4 0

3 years ago

Can you please help me

Slav-nsk [51]

Answer:

Step-by-step explanation:

Hi there!

To answer this, we must set it up as

$3x(2x^4-12x^2+7)$

Now we just use the distributive property to solve.

this becomes $6x^5-36x^3+21x$

I hope this helps!

4 0

3 years ago

I pay 25,000 for a car it depreciates at a rate of 10% what is the value of the car in 7 year

Murrr4er [49]

Answer:

2500

Step-by-step explanation:

7 0

3 years ago