Total number of sections on the spinner = 4
So there can be 4 outcomes on 1 spin of the arrow on the arrow.
Number of faces of the cube = 6
So there can be 6 outcomes on rolling of the dice.
For each outcome of the spinner, there can be 6 outcomes of rolling a dice. So for 4 outcomes of the spinner, there will be 6 x 4 = 24 outcomes in total.
For example, WW and either of {1,2,3,4,5,6} can occur. This makes folloiwng 6 outcomes: WW1, WW2, WW3, WW4, WW5 and WW6
Same goes for XX (6 outcomes), YY (6 outcomes) and ZZ (6 outcomes)
Thus in total there will be 24 outcomes.
So option j gives the correct answer
36 divided by 0.8 = 45
45 makers will be placed along the route
Answer:
An interval that will likely include the proportion of students in the population of twelfth-graders who carry more than $15 is 960
Step-by-step explanation:
For example, Condition 1: n(.05)≤N
• The sample size (10) is less than 5% of the population (millions of musicians), so
the condition is met.
• Condition 2: np(1-p)≥10
• =
2
10
= .2
• 1 − = 10 .2 1 − .2 = 1.6 . This is less than 10 so this condition is not
met.
It would not be practical to construct the confidence interval.
This is a vertical line that goes through all points with an x-coordinate of -9.
To graph it, I can give you a couple of points this line goes through so you can draw it more easily.
Points that are on line: (-9,0) and (-9,1)
Answer:
Step-by-step explanation:
There are 200 dice out of which 199 are fair
Prob for 6 in one special die = 1 and
Prob for 6 in other die = 1/6
A1- drawing special die and A2 = drawing any other die
A1 and A2 are mutually exclusive and exhaustive
P(A1) = 1/200 and P(A2) = 199/200
B = getting 6
i) Required probability
= P(A1/B) = 
P(A1B) = 
P(A2B) = 
P(B) = 
P(A1/B) = 
P(A2/B) = 
