Answer:
From the looks of it I think the answer is C.
Answer:
<em>2.5 hours</em>
<u>Skills needed: Speed, distance, time problems</u>
Step-by-step explanation:
1) We are given speed and distance, and have to find out the the time (in hours).
- In terms of units, everything is matched up (Since distance and speed use kilometers, and speed and time use hours).
- Time is always the distance you travelled (how far) divided by how fast you travelled (the rate/speed)
---> We can use the formula for time: 
t= time
d=distance
r=rate/speed
2) Now, let's plug in for distance and rate.
---> 
2.5 hours is the answer.
Answer:
AAS
Step-by-step explanation:
First, write down the given.
1. ∠V≅∠Y - Given
Since line WZ bisects ∠YWZ, which in other words splits it in half, that means that
2. ∠VWZ ≅ ∠YWZ - angle bisector
3. WZ ≅ ZW - reflexive property
Making the theorem AAS
99 would be to more than 89 because 89+10= 99<span />
Answer:
See below.
Step-by-step explanation:
The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.
The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.
(a) h(t) = 64t - 1/2*32 t^2
h(t) = 64t - 16t^2.
(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).
The y-axis is the height of the rocket and the x-axis gives the time.
Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.
