Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
C) 2,6,24,120,720
Step-by-step explanation:
Here the n-th term An =
A1 is the first term
A1 = (1 + 2)!/(1 + 2)
= 3!/3
A1 = 2
A2 is the second term
A2 = (2 +2)!/(2 +2)
= 4!/4
A2 = (1*2*3*4) /4
A2 = 6
A3 is the third term
A3 = (3 + 2)!/(3 +2)
A3 = 5!/5
A3 = 24
A4 is the fourth term
A4 = (4 + 2)!/(4 + 2)
A4 = 6!/6
A4 = 120
A5 is the fifth term
A5 = (5 + 2)!/(5 +2)
A5 = 7!/7
A5 = 720
Answer: C) 2,6,24,120,720
Thank you.
Answer:
Z.
Step-by-step explanation:
I wrote down the subject with the number of students. I looked one by one to see if the number of students with the subject matched with the graph. Then I finally found that the last graph matched with what I written down.
No, 1/2 is bigger than 1/3 because:-
1/2 = 3/6
1/3 = 2/6
Compare
3/6 is larger, which means 1/2 is larger since they both equal each other.
Answer: 1/2 is greater than 1/3
Answer:
14
Step-by-step explanation:
6(2)
12
4÷2
2
12+2
pemdas