Answer:
D. 803 lbs
Explanation:
In order to find the compressive stress on all three blocks we first need to find the normal surface area of each:
Surface Area of 1 Block = 3.5 x 3.5
Surface Area of 1 Block = 12.25
Surface Area of all 3 Blocks = A = 3 x 12.25
Area = 36.75
Now, the stress is given by the following formula:
Stress = Force/Area
Stress = 29500 lbs/36.75
Stress = 802.72 lbs
Hence, the correct option will be:
<u>D. 803 lbs</u>
Answer:
Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3).
Solution —
Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g
No. of moles of CaCO3
= No. of molecules/Avogadro constant
= 6.022 × 1023/ 6.022 × 1023
= 1 mole
Mass of CaCO3
= No. of moles × molar mass
= 1 × 100 g = 100 g.
The scientist that contributed to the declassification of Pluto as a planet is Mike Brown.
Hi!
The correct answer is : <u>either stretch or compress the spring</u>
<h3>Explanation</h3>
The spring constant, denoted commonly as k, is a component of Hooke's law which describes the force that is required to compress or stretch an object to be directly proportional to the length of extension or compression.
F ∝ x
where F is the force applied to the spring, and x is the length of extension or compression.
The equation of Hooke's law is consequently
F = kx
where k is a non zero constant, known as the spring constant.
<h3>Hope this helps!</h3>
You look at the units you want, then try to figure out which units ti multiply by to get the units you have to match the units you want. For example, if you want kg/m^3 and have m/s
You can see that you have a length/time(lets denote it d/t for distance over time) and want mass/volume (lets denote it m/d^3). d/t multiplied by time=d but we want m/d^3 so lets multiply our original d/t by time(t) and mass(m) so d/t(t) (m) =dm. However, we want m/d^3 so we will also have to divide by d^4.
(d/t)(t)(m) /(d^4)=m/d^3 = mass/length^3 =mass/volume which was what we wanted our end result to be.
