Answer:
wave front
Explanation:
wave front is an imaginary line of a wave that joins all adjacent points that are in phase,
so that's the definition, and you apply it to the question
it obviously can't be the rest
hope you get it
please mark it brainliest
The given question is incomplete. The complete question is:
Estimate the volume of each ball. Use the formula
where v is the volume and r is the radius. record the volume in table A of your student guide. The radius of the tennis ball is 2.1 cm and the radius of thr golf ball is 2.0 cm. What is the estimated volume of the table tennis ball in
What is the estimated volume of the golf ball in
Answer: Volume of the tennis ball is
and Volume of the golf ball is 
Explanation:
We have to find the Volume of tennis ball and golf ball by using the formula 
Radius of the tennis ball = 2.1 cm
Radius of the golf ball =2.0 cm.
Putting the value of radius in the formula , we get:
Volume of the tennis ball = 
Volume of the golf ball = 
Volume of the tennis ball is
and Volume of the golf ball is 
Answer:
W = 600 J
Explanation:
We have,
According to attached figure,
Height of the inclined plane is 60 m
Force acting on the block is 10 N
It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :
W = mgh
or

So, the work done against the gravity is 600 J.
Answer:
a = 5 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.

where:
Vf = final velocity = 20 [m/s]
Vo = initial velocity = 10 [m/s]
t = time = 2 [s]
a = acceleration [m/s²]
Now replacing:
![20 =10 +a*2\\10=2*a\\a=5[m/s^{2} ]](https://tex.z-dn.net/?f=20%20%3D10%20%2Ba%2A2%5C%5C10%3D2%2Aa%5C%5Ca%3D5%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
k_2 = 7.815 * 10^-3 s^-1
Explanation:
Given:
- rate constant of reaction k_1 = 7.8 * 10^-3 s^-1 @ T_1 = 25 C
- rate constant of reaction k_2 = ? @ T_2 = 75 C
- The activation energy E_a = 33.6 KJ/mol
- Gas constant R = 8.314472 KJ / mol . K
Find:
- rate of reaction k_2 @ T_2 = 75 C
Solution:
- we will use a combined form of Arrhenius equations that relates rate constants k as function of E_a and temperatures as follows:
k_2 = k_1 * e ^ [(E_a / R) * ( 1 / T_1 - 1 / T_2 )
- Evaluate k_2 = 7.8 * 10^-3* e^[(33.6 / 8.314472)*(1/298 -1/348)
- Hence, k_2 = 7.815 * 10^-3 s^-1