Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer is C:9
12^9/12^5 = 12^4
hope it helps
<h2>
Answer:
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Step-by-step explanation:
Step 1: Multiply the whole number part (1) by the denominator (8).
1 × 8 = 8
Step 2: Add the product from Step 1 (8) to the numerator (4).
8 + 4 = 12
Step 3: Write that result (12) above the denominator. So,
Step 4: The fraction 
Can be reduced by dividing both numerator and denominator by the GCD(12,8) = 4. Thus,
2-1 reversed is turning it around : 1-2 which equals -1 because there is one left over. B is your answer and hoped I helped!
3+ x/4=8
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