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3 years ago

Suppose y varies inversely with x. Write an equation if y=-3 when x=17

Mathematics

1 answer:

vodka [1.7K]3 years ago

6 0

Answer:

y = -51 ÷ x

Step-by-step explanation:

The standard format of a inversely proportional equation goes by the format of y = k ÷ x. The question asks us to write an equation if y = -3 when x = 17 and y varies inversely with x.

So we substitute the values y = -3 and x = 17 in the equation y = k ÷ x

K = constant, we have to work this out

-3 = k ÷ 17

-3 × 17 = k

k = -3 × 17

k = -51

k = -51 So then we put this back into the original y = k ÷ x to find our final equation which is y = -51 ÷ x

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umka2103 [35]

Since, the number w and 0.8 are additive inverses.

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The graph of $y = ax^2 + bx + c$ is shown below. Find $a \cdot b \cdot c$. (The distance between the grid lines is one unit.)

Savatey [412]

Answer:

$a\cdot b\cdot c=\frac{15}{4}$

Step-by-step explanation:

Vertex is the minimum or maximum point of parabola

Vertex of parabola is (h,k)

Therefore, from given graph (-3,-2) is the lowest point.

Vertex of parabola is at (-3,-2).

Standard equation of parabola

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Substitute the values

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$y+2=a(x+3)^2$

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Therefore, it satisfied the equation of parabola.

$0+2=a(-1+3)^2=4a$

$a=2/4=1/2$

Now, using the value of a

$y+2=1/2(x+3)^2=1/2(x^2+6x+9)$

$y+2=\frac{1}{2}x^2+3x+\frac{9}{2}$

$y=\frac{1}{2}x^2+3x+\frac{9}{2}-2$

$y=\frac{1}{2}x^2+3x+\frac{9-4}{2}$

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By comparing with

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We get

$a=\frac{1}{2}, b=3, c=5/2$

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3 years ago

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Answer:

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since when x is 0, and y is -5, you know that the y intercept is -5.

look at the table

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tiny-mole [99]

A way to add fractions that always works is to multiply each numerator by the denominator of the other, then express the sum of products over the product of the denominators.
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Here, you have
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