this is false
(6+8)^2= 196
6^2+8^2=100
They are not equal so this is a false statement
That question is accompanied by these answer choices:
<span>A. The scale is accurate but not precise.
B. The scale is precise but not accurate.
C. The scale is neither precise nor accurate.
D. The scale is both accurate and precise.
Then you need to distinguish between accuracy and precision.
Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report.
The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.
So, the answer is that the scale is precise but not accurate (the option B</span>
The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.
To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.
By definition of absolute value,
Over this particular integration interval,
• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and
• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5
so you end up splitting the integral at <em>t</em> = <em>π</em> as
Now compute the distance:
making B the correct answer.
Answer:
a= 35°
b= 45°
c= 60°
Step-by-step explanation:
