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dimaraw [331]
3 years ago
9

The diameter of a circle is 8 kilometers. What is the radius?

Mathematics
1 answer:
OLga [1]3 years ago
7 0
The radius is 4 kilometers
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If 2 divided by 2 is 1 what is 1 divided by 1?
Kaylis [27]

Answer:

1

Step-by-step explanation:

1 goes into 1 one time so it = 1

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3 years ago
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2logx=3-2log(x+3) solve for x​
AVprozaik [17]

Answer:

\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}

Step-by-step explanation:

2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}

x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D

6 0
3 years ago
Form a quadratic equation with roots (1+√3) and (1-√3)​
Alborosie

Answer:

hope this helps u

I guess

7 0
2 years ago
A manufacturing company with 450 employees begins a new product line and must increase their number buy 18% how many total emplo
Soloha48 [4]

Answer:

After increasing their employees by 18% they will now have 531 total employees.

Step-by-step explanation:

0.18 x 450 = 81

81 + 450 = 531

7 0
3 years ago
The difference between 48 and 13 algebra numeral expression.
Sphinxa [80]

Numerical expressions contain numbers, while algebraic expressions contain variables and numbers.

<u>Numerical Expression</u>

"Difference" indicates that we'll be subtracting 13 from 48.

48 - 13 = 35

<u>Algebraic Expression</u>

Variables represent the unknown number, in this case the difference between 48 and 13. Let d represent the difference between the two.

48 - 13 = d

35 = d

6 0
3 years ago
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