The diameter of a circle is 8 kilometers. What is the radius?

I need help ASAP Integrated math II

Molodets [167]

Answer:

$\boxed{ \bold{ \sf{x = 16}}}$

$\boxed{ \bold{ \sf{m < AFD = 82}}}$

Step-by-step explanation:

$\sf{5x + 18 = 3x + 50}$

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒ $\sf{5x - 3x = 50 - 18}$

Collect like terms

⇒ $\sf{2x = 50 - 18}$

Subtract 18 from 50

⇒ $\sf{2x = 32}$

Divide both sides of the equation by 2

⇒ $\sf{ \frac{2x}{2} = \frac{32}{2} }$

Calculate

⇒ $\sf{x = 16}$

The value of x is 16

Now, let's find value of m<AFD :

$\sf{m < afd + 5x + 18 = 180}$ ( sum of angle in straight line )

plug the value of x

⇒ $\sf{m < AFD + 5 \times 16 + 18 = 180}$

Multiply the numbers

⇒ $\sf{m < AFD + 80 + 18 = 180}$

Add the numbers

⇒ $\sf{m < AFD + 98 = 180}$

Move constant to R.H.S and change it's sign

⇒ $\sf{m < AFD = 180 - 98}$

Subtract 98 from 180

⇒ $\sf{m < AFD = 82}$

Value of m<AFD = 82

Hope I helped!

Best regards!!

3 0

2 years ago

How many different tables of 4 can you make from 16 potential bridge players? How many different tables if 4 players insist on p

Nadusha1986 [10]

4 tables. 4*4 is 16, meaning that even if 4 players want to sit together it doesn't make a difference. With 16 players and 4 at a table we are going to need 4 tables.

8 0

2 years ago

Read 2 more answers

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Four hu

castortr0y [4]

Answer: h = 120 ft; w = 80 ft

A = 9600 ft^2

Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:

A = h*w (eq1)

The total amount of fence used is:

L = 2*h + 2*w + w (eq2) (an extra distance w beacuse of the division)

Solving for w:

w = L - 2/3*h = 480 - 2/3*h (eq3) Replacing this into the area eq:

We derive this and equal zero to find its maximum:

Solving for h:

h = 120 ft. Replacing this into eq3:

w = 80ft

Therefore the maximum area is:

A = 9600 ft^2

5 0

2 years ago

Find the minimum or maximum value of the function. What is the H? (Desmos)

beks73 [17]

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3( $x^{2}$ -4x)+16

=3( $x^{2}$ -4x+4-4)+16 (- For the balance of equation, and attention 1)

=3 $(x-2)^{2}$ -3*4+16

=3 $(x-2)^{2}$ +4

<h3>Attention:</h3>

1. $(a-b)^{2}=a^{2} -2ab+b^{2}$

2. The formula for the vertex form is y = $a(x-h)^{2}+k$ , the vertex is (h,k)

4 0

2 years ago

Solve for 5+n/8=4 show your work

Aleks [24]

Answer:

n = -8

Step-by-step explanation:

5+n/8=4

Subtract 5 from each side

5-5+n/8=4-5

n/8 = -1

Multiply each side by 8

n/8 * 8 = -1 *8

n = -8

5 0

2 years ago