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Vlad [161]
3 years ago
15

Will mark brainest help please !!!

Mathematics
1 answer:
amm18123 years ago
7 0

8) red and 1, red and 2, red and 3, blue and 1, blue and 2, blue and 3

So answer is 6

9) 0.5*1/3 = 0.17

10) 0.5*2/3 = 0.33

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The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
3 years ago
Please help !!!!!!!!!!
Salsk061 [2.6K]
D.3.1 is the greatest value from the list.
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Read 2 more answers
HELPPPPPPP ASAPPPPPPPP PLSSSS
Novay_Z [31]

Answer:

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