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3 years ago

What is the experimental probability that you will get exactly 2 out of the three correct

Mathematics

1 answer:

Dmitry [639]3 years ago

7 0

Oh ok so the answer is .666666666666 etc infinite 6s

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Mrs. Wingate has 10 students in her math class. The line plot shows the number of hours students spent doing homework last week.

klio [65]

A. 35 because of you look at the line plot it explains how long student are in there for and how many times a day. So you just need to figure out how many students do hw for how long and then multiply that by 10.

8 0

3 years ago

A train slows down as it rounds a sharp horizontal turn, going from 92.0 km/h to 54.0 km/h in the 16.0 s that it takes to round

Mnenie [13.5K]

Calculation of centripetal acceleration(ac):

$a_c=\frac{v^2}{r}$

we can change our speed in terms of m/s

$v=54km/h=54*\frac{1000}{3600} m/s$

now, we can plug these values

$a_c=\frac{(54*\frac{1000}{3600})^2}{130}$

$a_c=1.73077m/s^2$

Calculation of tangential acceleration(at):

$a_t=\frac{\Delta v}{\Delta t}$

now, we can plug values

$a_t=\frac{(54-92)*\frac{1000}{3600} }{16}$

now, we can simplify it

$a_t=-0.65972 m/s^2$

Calculation of resultant acceleration:

$a=\sqrt{(a_c)^2+(a_t)^2}$

now, we can plug values

$a=\sqrt{(1.73077)^2+(-0.65972)^2}$

$a=1.85224m/s^2$ .............Answer

4 0

3 years ago

You are given a problem that involves multiplying a positive number and a negative number. Which of the following are reasonable

crimeas [40]

First question:. A and D. Second question: B and C .

7 0

3 years ago

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A grocery store sells 6 bottles of water for $4.80 and 18 bottles of water for $22.50. Is the cost proportional to the number so

zhuklara [117]

No the cost is not proportional to the number sold.

6 bottles divided by $4.80 = .80 each
18 bottles divided by $22.50 = $1.25 each

3 0

3 years ago

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What is the period of the sinusoid given by y=-4sin( <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%CF%80%7D%7B3%7D%20" id="Te

Sonja [21]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
$

$\bf \bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

with that template in mind, let's see

$\bf \begin{array}{llll}
y=&-4sin(&\frac{2\pi }{3}x)\\
&A&B
\end{array}\qquad period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{2\pi }{3}}\implies \cfrac{\frac{2\pi }{1}}{\frac{2\pi }{3}}
\\\\\\
\cfrac{2\pi }{1}\cdot \cfrac{3}{2\pi }\implies 3$

8 0

3 years ago

Read 2 more answers