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HACTEHA [7]
3 years ago
9

Ohm's law relates the current, voltage, and resistance in a circuit. Use Ohm's law to determine what will happen to the remainin

g variable if one is held constant and another is changed. Assume that, originally, the resistance is R 0 , the current is I 0 , and the voltage is V 0 .
Physics
2 answers:
larisa [96]3 years ago
4 0

Answer:

Ohm's Law states that current through any conductor is directly proportional to the potential difference across the ends of the conductor.

Explanation:

Ohm's Law states that current through any conductor is directly proportional to the potential difference across the ends of the conductor.

<u>Mathematically:</u>

I\propto V

I_0=\frac{V_0}{R_0}

where

R = resistance of the conductor

i.e.

  • When resistance is held constant the current is directly proportional to the voltage.

Other form of the equation is:

V_0=R_0.I_0

  • For a constant current the voltage is directly proportional to the resistance of the conductor.

V_0\propto R_0

  • For constant voltage the current is inversely proportional to the resistance of the conductor.

I_0\propto \frac{1}{R_0}

Ivanshal [37]3 years ago
3 0

Answer:

Explanation:

According to the Ohm's law, when the temperature of a conductor remains constant, the current flowing through the conductor is directly proportional to the potential difference applied across the conductor.

V = I R

where, I is the current and R be the resistance of the conductor.

When the resistance remains constant, if we increase the potential difference across the conductor, the current also increases.

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A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
ikadub [295]

Answer:

b) No acceleration in the vertical

c) 35N

d) 35N

e) 8.75\ m/sec^2

Explanation:

a) The situation can be shown in the free body diagram shown in the figure below where F is the applied force, Fr is the friction force, W is the weight of the book and N is the normal force exerted vertically up from the desk to the book

b) The vertical movement is restrained by the normal force which opposes to the weight. In absence of any other force, they both are in equilibrium and the net force is zero

c) The net horizontal force acting on the book is the vectorial sum of the applied force and the friction force. Since they lie in the same axis and are opposed to each other:

Fh_{net}=F-F_r=50 N - 15N=35N

d) The net force acting on the book is the vector sum of all forces in all axes. The normal and the weight cancel each other in the y-axis, so our resulting force is the x-axis net force, computed as above:

F_n=35N in the x-axis

e) Following Newton's second law, the acceleration is calculated as

a=\frac{F_t}{m}=\frac{35N}{4Kg}=8.75m/sec^2

8 0
3 years ago
The pressure inside a blimp is 506 Pa, if the area is 3,000cm2 then what is the force? ​
Zarrin [17]

Answer:

<h2>151.8 N</h2>

Explanation:

The force acting on the blimp can be found by using the formula

<h3>f = p × a</h3>

p is the pressure

a is the area

3000 cm² = 0.3 m²

From the question we have

f = 506 × 0.3

We have the final answer as

<h3>151.8 N</h3>

Hope this helps you

6 0
3 years ago
A cord of mass 0.65 kg is stretched between two supports 28 m apart. if the tension in the cord is 150 n, 2 how long will it tak
MaRussiya [10]
Ans: Time <span>taken by a pulse to travel from one support to the other = 0.348s
</span>
Explanation:
First you need to find out the speed of the wave.

Since
Speed = v = \sqrt{ \frac{T}{\mu} }

Where
T = Tension in the cord = 150N
μ = Mass per unit length = mass/Length = 0.65/28 = 0.0232 kg/m

So
v = \sqrt{ \frac{150}{0.0232} } = 80.41 m/s

Now the time-taken by the wave = t = Length/speed = 28/80.41=0.348s
5 0
3 years ago
A ball is tossed with enough speed straight up so that it is in the air several seconds. (a) What is the velocity of the ball wh
irina1246 [14]

(a) Zero

When the ball reaches its highest point, the direction of motion of the ball reverses (from upward to downward). This means that the velocity is changing sign: this also means that at that moment, the velocity must be zero.

This can be also understood in terms of conservation of energy: when the ball is tossed up, initially it has kinetic energy

K=\frac{1}{2}mv^2

where m is the ball's mass and v is the initial speed. As it goes up, this kinetic energy is converted into potential energy, and when the ball reaches the highest point, all the kinetic energy has been converted into potential energy:

U=mgh

where g is the gravitational acceleration and h is the height of the ball at highest point. At that point, therefore, the potential energy is maximum, while the kinetic energy is zero, and so the velocity is also zero.

(b) 9.8 m/s upward

We can find the velocity of the ball 1 s before reaching its highest point by using the equation:

a=\frac{v-u}{t}

where

a = g = -9.8 m/s^2 is the acceleration due to gravity, which is negative since it points downward

v = 0 is the final velocity (at the highest point)

u is the initial velocity

t = 1 s is the time interval

Solving for u, we find

u=v-at = 0 -(-9.8 m/s^2)(1 s)= +9.8 m/s

and the positive sign means it points upward.

(c) -9.8 m/s

The change in velocity during the 1-s interval is given by

\Delta v = v -u

where

v = 0 is the final velocity (at the highest point)

u = 9.8 m/s is the initial velocity

Substituting, we find

\Delta v = 0 - (+9.8 m/s)=-9.8 m/s

(d) 9.8 m/s downward

We can find the velocity of the ball 1 s after reaching its highest point by using again the equation:

a=\frac{v-u}{t}

where this time we have

a = g = -9.8 m/s^2 is the acceleration due to gravity, still negative

v  is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

t = 1 s is the time interval

Solving for v, we find

v = u+at = 0 +(-9.8 m/s^2)(1 s)= -9.8 m/s

and the negative sign means it points downward.

(e) -9.8 m/s

The change in velocity during the 1-s interval is given by

\Delta v = v -u

where here we have

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

Substituting, we find

\Delta v = -9.8 m/s - 0=-9.8 m/s

(f) -19.6 m/s

The change in velocity during the overall 2-s interval is given by

\Delta v = v -u

where in this case we have:

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = +9.8 m/s is the initial velocity (1 s before reaching the highest point)

Substituting, we find

\Delta v = -9.8 m/s - (+9.8 m/s)=-19.6 m/s

(g) -9.8 m/s^2

There is always one force acting on the ball during the motion: the force of gravity, which is given by

F=mg

where

m is the mass of the ball

g = -9.8 m/s^2 is the acceleration due to gravity

According to Newton's second law, the resultant of the forces acting on the body is equal to the product of mass and acceleration (a), so

mg = ma

which means that the acceleration is

a= g = -9.8 m/s^2

and the negative sign means it points downward.

7 0
3 years ago
What is an independent variable
snow_tiger [21]

Answer:

A variable (often denoted by x ) whose variation does not depend on that of another.

Explanation:

8 0
3 years ago
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