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Thepotemich [5.8K]
3 years ago
7

If a baseball pitch leaves the pitcher's hand horizontally at a velocity of 150 km/h by what percent will the pull of gravity ch

ange the magnitude of the velocity when the ball reaches the batter, 18 m away? for this estimate, ignore air resistance and spin on the ball.
Physics
1 answer:
Slav-nsk [51]3 years ago
8 0
<span>0.52% First, let's convert that speed into m/s. 150 km/h * 1000 m/km / 3600 s/h = 41.667 m/s Now let's see how much time gravity has to work on the ball. Divide the distance by the speed. 18 m / 41.667 m/s = 0.431996544 s Now multiply that time by the gravitational acceleration to see what the vertical component to the ball's speed that gravity adds. 0.431996544 s * 9.8 m/s^2 = 4.233566131 m/s Use the pythagorean theorem to get the new velocity of the ball. sqrt(41.667^2 + 4.234^2) = 41.882 m/s Finally, let's see what the difference is (41.882 - 41.667)/41.667 = 0.005159959 = 0.5159959% Rounding to 2 figures, gives 0.52%</span>
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The formula can be used to convert temperatures between degrees Fahrenheit () and degrees Celsius (). How many degrees are in th
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Answer:

-30°C

Explanation:

F-32/180 =C-0/100

or, -22-32/180=C/100

or, -54/180*100=C

or, -0.3*100=C

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8 0
2 years ago
A garden hose has a radius of 0.0120 m, and water initially comes out at a speed of 2.88m/s. Dasha puts her thumb over the end ,
creativ13 [48]

Answer:

v = 12.4 [m/s]

Explanation:

With the speed and Area information, we can determine the volumetric flow.

V=v*A\\A=\pi *r^{2}

where:

r = radius = 0.0120 [m]

v = 2.88 [m/s]

A=\pi *(0.0120)^{2} \\A=4.523*10^{-4} [m]\\

Therefore the flow is:

V=2.88*4.523*10^{-4} \\V=1.302*10^{-3} [m^{3}/s ]

Despite the fact that you cover the inlet with the finger, the volumetric flow rate is the same.

v=V/A\\v=1.302*10^{-3} /1.05*10^{-4} \\v=12.4[m/s]

3 0
3 years ago
Astronomical observatories have been available since ancient times, and many cultures set aside special sites for astronomical o
inysia [295]

Answer:

Telescope

Explanation:

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This was first constructed by Hans Lippershey in the year 1608.

6 0
3 years ago
HELP ANSWER QUESTION 1
arsen [322]
The width is 2.5 cm long and could not be the right answer
5 0
3 years ago
We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 4.2
monitta

Answer:

The number of atoms is N = 4.37*10^{22} \ atoms

Explanation:

From the question we are told that

                 The mass of coin  is m_n = 4.2g

                   Number of atom in one mole = n =6.02*10^{23} \ atoms

                   Molar mass of nickel M = 57.8g

Now the relation to obtain the number of atom in  the  nickel coin is

                        N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel }  * No\ of\atoms \ in \ \ one\  mole\ of\ nickel

                           = \frac{4.2}{57.8}* 6.02*10^{23}

                           =4.37 *10^{22} atoms

                 

     

8 0
3 years ago
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