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3 years ago

What is the dollar amount of the Gentry's annual food and housing budgets combined?

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

3 0

Answer:

The combined amount is $14871.21.

Step-by-step explanation:

It is given that, the total yearly income of gentry family is $29742.42

The % charge on income for food is 20%.

The % charge on income for housing is 30%.

The amount in dollar from % form is given by,

= $(\frac{percent form}{100})(annual income)$

For annual food,

= $(\frac{20}{100})(29742.42)$

= $5948.484

For housing budgets,

= $(\frac{30}{100})(29742.42)$

= $8922.726

Thus the combined amount is,

= $8922.726 + 5948.484 = 14871.21$

= $14871.21

Read more on solving equations;

brainly.com/question/2972832

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4 0

2 years ago

Find the marked prices of the following , given the percentage discount and the sale prices: part a: 12% discount , and the sale

Anna [14]

Answer:

A) $87.5

B) $164

Step-by-step explanation:

A) Marked Price (Original Price)

= $\frac{Sale Price}{1 -Discount}$

= $\frac{77}{1-0.12}$

=87.5

B) Marked Price (Original Price)

= $\frac{Sale Price}{1 -Discount}$

= $\frac{123}{1-0.25}$

=164

6 0

3 years ago

Jane has a checkbook balance of $68.00. She then writes two checks, one for $5.00 and one for $62.50. She also deposits $75.00.

andrew-mc [135]

The answer here would be C. ON/C 6 8 – 5 – 6 2 . 5 0 + 7 5 =

Following her keypresses, she has to turn the calculator on by pressing "ON/C". Entering her current balance, she presses 6 then 8, subtracting her 2 checks by entering "-" then 5, and again for 62.50. Lastly, she adds the amount deposited which is 75. Pressing the "=" sign then tells her how much her new balance is.

8 0

3 years ago

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

7 0

3 years ago

When simplifying x3. x2, the exponents are added together. True False

gladu [14]

When simplifying x3. X2, the exponents are added together true of false
Your answer is true

5 0

2 years ago