All categories

2 years ago

In a class 20 of students, 7 have a cat and

Mathematics

1 answer:

blsea [12.9K]2 years ago

8 0

Answer:

$\frac{3}{20}$

Step-by-step explanation:

Since there are 20 students, this will be the denominator.

Now, to find how many students have a dog and a cat, you need to subtract all the numbers with 20. The leftover number will be the amount of students.

7+8+8=23

23-20=3

So, there are 3 students who have a dog and a cat.

So, the fraction will be $\frac{3}{20}$

You might be interested in

Any kind soul willing to help a random person lol

Romashka-Z-Leto [24]

Um i got 6,42 rounded

7 0

3 years ago

Adam drove his car 132 km and used 11 liters of fuel. How many kilometers will he cover with 14 liters of fuel?

Sever21 [200]

168km, hope it helps

5 0

3 years ago

Read 2 more answers

A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Write an expression to re

gizmo_the_mogwai [7]

Exponential growth of the form:

F=Ar^t

F=100(1.22)^t

F(5)=100(1.22)^5

F(5)=270.27

F(5)=270 to the nearest frog...

....

1.22=r^12

r=1.22^(1/12)

F=100(1.22^(1/12)^t)

F=100(1.22^(t/12)) now it will produce monthly populations...

Say we did the same as before but instead of 5 years you have 60 months...

F(60)=100(1.22^(60/12))

F(60)=270 to the nearest frog... :P

6 0

3 years ago

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$