Answer:
1.16cm were cut off the end of the second pipe
Explanation:
The fundamental frequency in the first pipe is,
<em><u>Since the speed of sound is not given in the question, we would assume it to be 340m/s</u></em>
f1 = v/4L, where v is the speed of sound and L is the length of the pipe
266 = 340/4L
L = 0.31954 m = 0.32 m
It is given that the second pipe is identical to the first pipe by cutting off a portion of the open end. So, consider L’ be the length that was cut from the first pipe.
<u>So, the length of the second pipe is L – L’</u>
Then, the fundamental frequency in the second pipe is
f2 = v/4(L - L’)
<u>The beat frequency due to the fundamental frequencies of the first and second pipe is</u>
f2 – f1 = 10hz
[v/4(L - L’)] – 266 = 10
[v/4(L – L’)] = 10 + 266
[v/4(L – L’)] = 276
(L - L’) = v/(4 x 276)
(L – L’) = 340/(4 x 276)
(L – L’) = 0.30797
L’ = 0.31954 – 0.30797
L’ = 0.01157 m = 1.157 cm ≅ 1.16cm
Hence, 1.16 cm were cut from the end of the second pipe
The momentum of an object is the product between the mass m of the object and its velocity:
The truck in our problem has momentum equal to
and a mass of
so, if we re-arrange the previous formula, we can use these data to find the velocity of the truck:
Answer:
No
Explanation:
In the photoelectric effect,
The number of the electrons which are being emitted is directly proportional to the intensity of the light and is independent on the frequency of the incident radiation of the light which has the frequency greater than the threshold frequency.
Thus, on increasing the frequency of the light which is being shinned on the metal , there is no change in the electrons which are being emitted.
"Light through a vacuum" is the one among the following choices given in the question that shows which can travel at the greatest speed. The correct option among all the options that are given in the question is the fourth option or option "D". I hope that this is the answer that has come to your desired help.
