Answer:
C_d = 0.942
Explanation:
Let's first calculate the angle of inclination.
Formula is;
tan θ = (%slope)
% Slope is given as 12%
Thus;
θ = tan^(-1) (12/100)
θ = 6.843°
Let's now calculate the force due to the weight of the rider and bike combined from;
F = mg sin θ
We are given; m = 100 kg.
Thus;
F = 100 × 9.81 × sin 6.843
F = 116.885 N
The drag force will also be the same as the force due to the weight of the body. Thus;
Drag force; F = C_d(½ρu²A)
Where;
C_d is drag coefficient
ρ is density
U is terminal speed
A is area
We are given;
A = 0.9 m²
U = 15 m/s
From online tables, density of air is approximately 1.225 kg/m³
Thus;
116.885 = C_d(½ × 1.225 × 15² × 0.9)
116.885 = 124.03125C_d
C_d = 116.885/124.03125
C_d = 0.942
Answer:
Explained
Explanation:
A) The total energy of the system is defined by the energy at maximum amplitude, which we'll call A. At that point, the energy of the system is
E = 1/2×m×A^2;
since energy is conserved, this is also the total amount of energy that the system ever has.
So at x=1/2A,
the potential energy of the system is 1/8×m×A^2
which is one-fourth of the system's total energy. Therefore, the remaining three-fourths is kinetic.
B) (i) Doubling the maximum amplitude will quadruple the total energy:
(ii) Doubling the maximum amplitude will double the maximum velocity
(iii) Doubling the maximum amplitude will double the maximum acceleration: m×a = -k(2A)
(iv) Doubling the maximum amplitude leaves the period unchanged:
(neither m nor k has changed).
Answer:
Two marbles are launched at t = 0 in the experiment illustrated in the figure below. Marble 1 is launched horizontally with a speed of 4.20 m/s from a height h = 0.950 m. Marble 2 is launched from ground level with a speed of 5.94 m/s at an angle above the horizontal. (a) Where would the marbles collide in the absence of gravity? Give the x and y coordinates of the collision point. (b) Where do the marbles collide given that gravity produces a downward acceleration of g = 9.81 m/s2? Give the x and y coordinates.
Explanation:
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