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dsp73
3 years ago
8

How many simple machines are in a wine opener? The kind with the bottle opener at the head and two "arms."

Physics
2 answers:
Blababa [14]3 years ago
7 0
It uses the corkscrew to anchor it to the cork and a lever to pull the cork out

Hope this helps buddy:D
Harlamova29_29 [7]3 years ago
4 0
The screw<span>. A corkscrew is a simple machine that is used to open bottles with corks. The </span>screw<span> works by twisting into the cork.

so there are 2 

hope this helps you all
and please make this a 
the braily-est answer
                                                                                       Thanks


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I’ll give brainliest and 10 points
schepotkina [342]
I think it is D. I hope this helps
4 0
3 years ago
Two people travel from Columbus to Cleveland, one by car at an average velocity of 90km/h, and one by plane at an average veloci
Flura [38]

Answer:

Explanation:

Yes , their displacement may be equal .

Suppose the displacement is AB where A is starting point and B is end point .

The car is covering the distance AB by going from A to B on straight line . On the other hand plane goes from A to C , then from C to D and then from D to B . In this way plane reaches B from A on a different path which is longer than path of the car . In the second case also displacement of plane is AB . In the second case distance covered is longer but displacement is same that is AB .

7 0
3 years ago
A flashing red traffic light at an intersection means
k0ka [10]
Just do what u would do if u were at a stop sign 
5 0
3 years ago
A bicycle wheel of radius 0.70 m is rolling without slipping on a horizontal surface with an angular speed of 2.0 rev/s when the
aleksandrvk [35]

Answer:

θ= 5 radian

Explanation:

Given data:

Radius r = 0.70 m

Initial angular speed ω_i = 2rev/s

Time t = 5 s

Final angular speed ω_f =0

so we have angular displacement

\theta= \frac{\omega_f-\omega_i}{2}\times t

putting values

\theta= \frac{0-2}{2}\times5 = 5 rad

8 0
3 years ago
A skateboarder, starting from rest, rolls down a 12.8-m ramp. When she arrives at the bottom of the ramp her speed is 8.89 m/s.
melamori03 [73]

Answer:

a) a = 3.09 m/s²

b) aₓ = 2.60 m/s²

Explanation:

a) The magnitude of her acceleration can be calculated using the following equation:

V_{f}^{2} = V_{0}^{2} + 2ad

<u>Where</u>:

V_{f}: is the final speed = 8.89 m/s

V_{0}: is the initial speed = 0 (since she starts from rest)

a: is the acceleration

d: is the distance = 12.8 m    

a = \frac{V_{f}^{2}}{2d} = \frac{(8.89 m/s)^{2}}{2*12.8 m} = 3.09 m/s^{2}

Therefore, the magnitude of her acceleration is 3.09 m/s².              

b) The component of her acceleration that is parallel to the ground is given by:

a_{x} = a*cos(\theta)

<u>Where</u>:

θ: is the angle respect to the ground = 32.6 °

a_{x} = 3.09 m/s^{2}*cos(32.6) = 2.60 m/s^{2}

Hence, the component of her acceleration that is parallel to the ground is 2.60 m/s².

I hope it helps you!

7 0
3 years ago
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