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3 years ago

Explain how an itty bitty bullet and a HUGE ship can both have a high momentum.

Physics

2 answers:

stich3 [128]3 years ago

8 0

Answer:

they both have or can cause damage to somthing or can both glide in certainb places

Explanation:

hope this helps i did my best

Crazy boy [7]3 years ago

5 0

They both can suck the skin off of my meat

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4 years ago

A machine has a mechanical advantage of 4.5. What force is put out by the machine if the force applied to the machine is 800 N?

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If the machine's mechanical advantage is 4.5, that means that

Output force = (4.5) x (Input force) .

We know the input force, and we need to find the output force. Rather than wander around the room looking at the floor while our hair smolders, let's try putting the numbers we know into the equation I wrote up there. OK ?

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3 years ago

Radar uses radio waves of a wavelength of 2.2 m . The time interval for one radiation pulse is 100 times larger than the time of

liq [111]

Answer:

<em>The shortest distance to an object that this radar can detect would be </em>

Explanation:

The shortest distance is the minimum distance that would be detected by the radar, The time of oscillation can be obtained thus;

T = 1/f ..........1

but f= v/λ substituting f into equation 1 we have;

T = λ/v...............2

Where λ is the wavelength = 2.2 m

v is the velocity of light since the radar is an electromagnetic wave

= 3 x $10^{8}$ m/s

T = 2.2 m / 3 x $10^{8}$ m/s

T = 7.33 x $10^{-9}$ s

<u>Calculating the time interval required by the pulse</u>

Since the interval of the pulse (t) is 100 times greater than the period of oscillation, the time of the pulse is expressed as;

t = 100 x T

t = 100 x 7.33 x $10^{-9}$ s

t = 7.33 x $10^{-7}$ s

Therefor the time of the pulse is 7.33 x $10^{-7}$ s

<u>Calculating for the shortest distance of the radar</u>

The shortest distance of the radar can be obtained using the equation below;

λ_s = (t/2) x v ............3

Substituting into equation 3 we have

λ_s = (7.33 x $10^{-7}$ /2) x 3 x $10^{8}$ m/s

λ_s = 111 m

Therefore the shortest distance to an object that this radar can detect would be 111 m

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