The circumference of a circle is 44 in. What is the area? (Use 22 for .)

Number 14 please help

liberstina [14]

I think you should say you multipliyed?

4 0

3 years ago

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What is -3(-6+8)^3-2(1-3)^3

marin [14]

Assignment: $\bold{Solve \ Equation: \ -3\left(-6+8\right)^3-2\left(1-3\right)^3}$

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Answer: $\boxed{\bold{-8}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Follow PEMDAS Order Of Operations; Calculate Within Parenthesis

Note: $\bold{PEMDAS: \ Parenthesis, \ Exponents, \ Multiply, \ Divide, \ Add, \ Subtract}$

$\bold{-6+8: \ 2}$

[ Step Two ] Rewrite Equation

$\bold{-3\cdot \:2^3-2\left(1-3\right)^3}$

[ Step Three ] Calculate Within Parenthesis

$\bold{1-3: \ -2}$

[ Step Four ] Rewrite Equation

$\bold{-3\cdot \:2^3-2\left(-2\right)^3}$

[ Step Five ] Calculate Exponents

$\bold{2^3: \ 8}$

[ Step Six ] Rewrite Equation

$\bold{-3\cdot \:8-2\left(-8\right)}$

[ Step Seven ] Multiply

$\bold{2\left(-8\right): \ -16}$

[ Step Eight ] Rewrite Equation

$\bold{-24-\left(-16\right)}$

[ Step Nine ] Subtract

$\bold{-24-\left(-16\right): \ -8}$

[ Step Ten ] Rewrite Equation

$\bold{-8}$

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$\bold{\rightarrow Mordancy \leftarrow}$

8 0

3 years ago

The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is $y=\frac{1}{3}x$

7 0

3 years ago

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What is the sum of the first five terms of a geometric series with a1=15 and r=1/3

Solnce55 [7]

Answer:

15, 5, 5/3, 5/9, 5/27

Step-by-step explanation:

Recall, that the general form of a geometric series is

a, ar, ar², ar³, .........

where a is the first term and r is the ratio

It is given that the first time is 15, hence a = 15

also given that ratio is 1/3

hence the first 5 terms are:

15, (15)(1/3), (15)(1/3)^2, (15)(1/3)^3, (15)(1/3)^4

simplifying each term gives

15, 5, 5/3, 5/9, 5/27

6 0

3 years ago

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Kay was walking along the bridge above the river. She accidentally lost her grip on her camera when she was trying to get it out

nikklg [1K]

Answer:

5 seconds it will hit the water.

Step-by-step explanation:

y=-16t²+400

add -16t² to both sides

-16t²=-400

divide both sides by 16

t²=-25

t=√25

t=5

8 0

3 years ago

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