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Lana71 [14]
3 years ago
9

What is the correct name for the compound, P2O5?

Chemistry
2 answers:
lina2011 [118]3 years ago
5 0

Answer : The correct name for the compound, P_2O_5 is, Diphosphorous pentoxide.

Explanation :

P_2O_5 is a covalent compound because in this compound the sharing of electrons takes place between phosphorous and oxygen. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

  • The less electronegative element is written first.
  • The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.
  • If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for the compound, P_2O_5 is, Diphosphorous pentoxide.

VikaD [51]3 years ago
4 0
DiPhosphorus pentoxide or pentaoxide
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Chemicals are classified as health hazards when they pose which of the following hazardous effects?
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Answer:

poisoning, breathing problems, skin rashes, allergic reactions, allergic sensitisation, cancer, and other health problems from exposure.

Explanation:

many hazardous chemicals are also classified as dangerous goods.

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2 years ago
What does I stand for?
tatuchka [14]
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7 0
3 years ago
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What is the change in boiling point for a 0.615m solution of Mgl2 in water?
ivanzaharov [21]

Answer :  The change in boiling point is, 0.94^oC

Explanation :

Formula used :

\Delta T_b=i\times K_f\times m

where,

\Delta T_b = change in boiling point = ?

i = Van't Hoff factor = 3 (for MgI₂ electrolyte)

K_f = boiling point constant for water = 0.51^oC/m

m = molality  = 0.615 m

Now put all the given values in this formula, we get

\Delta T_b=3\times (0.51^oC/m)\times 0.615m

\Delta T_b=0.94^oC

Therefore, the change in boiling point is, 0.94^oC

4 0
3 years ago
Definition: This is a net gain or loss of electrons.
AlekseyPX

Answer:

Elecric charge/ Electricity  

Explanation:

Electric charge is the net gain or loss of electrons

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3 0
2 years ago
In the world of chemistry, a 'mole' is a number of something... a very large number of something.
kipiarov [429]

Given:

No of atoms present= 8.022 x 10^23 atoms

Now we know that 1 mole= 6.022 x 10^23 atoms


Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.

Number of moles

= 8.022 x 10^23/6.022x 10^23

=1.3 moles.

Hence we have 1.3 moles present.

3 0
3 years ago
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