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Lana71 [14]
3 years ago
9

What is the correct name for the compound, P2O5?

Chemistry
2 answers:
lina2011 [118]3 years ago
5 0

Answer : The correct name for the compound, P_2O_5 is, Diphosphorous pentoxide.

Explanation :

P_2O_5 is a covalent compound because in this compound the sharing of electrons takes place between phosphorous and oxygen. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

  • The less electronegative element is written first.
  • The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.
  • If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for the compound, P_2O_5 is, Diphosphorous pentoxide.

VikaD [51]3 years ago
4 0
DiPhosphorus pentoxide or pentaoxide
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4 years ago
If the formation of NaCl proceeds according to the following equation and change in enthalpy, what is the reaction and change in
Sergio039 [100]

Answer:

  • <em>2NaCl → 2Na + Cl₂, ΔH = 822 kJ </em>

Explanation:

The chemical <em>equation</em> for the <em>formation of NaCl</em> is:

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That equation means that 1 mole of NaCl is formed by the reaction of 1 mole of Na and 1/2 mole of Cl₂, with a release of energy of 411 kJ.

The <em>decomposition</em> of <em>NaCl</em> is the inverse of the <em>formation</em> reaction; thus, you swift products and reactants and inverse the sign of the <em>change in enthalpy:</em>

  • NaCl → Na + 1/2 Cl₂, ΔH = 411 kJ

Since you want the decomposition of 2 moles you multiply the equation and the ΔH by 2:

  • 2NaCl → 2Na + Cl₂, ΔH = 822 kJ ← answer

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3 years ago
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