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NeX [460]
3 years ago
11

A projectile is fired upward with an initial speed vo on an airless world. A short time later, it comes back down and has a fina

l speed vo (just before it hits the ground).
What was the sign of the total work done by the force of gravity during the flight?

a.Wgrav=0

b.Wgrav < 0

c.Wgrav >0
Physics
1 answer:
Zinaida [17]3 years ago
7 0

Answer:

W_{grav} < 0

Explanation:

When a projectile is fired upwards with some initial speed then the it reaches the top of the projectile and then falls back to the ground.

According to the question we need to find the work done by the gravity which is acting downwards for the projectile when it is at a position just about to hit the ground in course of falling down.

As we know that work is given as:

W=F.s\cos\theta

here:

F= force of gravity on the object (which is acting downwards)

s= displacement of the object

  • Here the work done by the gravity at an instant just before the projectile hits the earth will be negative as the displacement is in the direction opposite to the force of gravity.
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MissTica

Answer:

Visible Light and Radio waves

Explanation:

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it is Partially transparent to Microwave and infrared range.

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A hiker travels south along a straight line path for 1.5 hours with an average velocity of 0.75 km/hr, then travels south for 2.
ANTONII [103]
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If a car is accelerating downhill under a net force 3674 N , what additional force would cause the car to have a constant veloci
Semenov [28]

Answer:

For the car to move with constant velocity the additional force required is  F__{dg} }=  -3674 \  N

Explanation:

From the question we are told that

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Generally the total  force acting on the  car is the net force plus the force due to gravity acting in direction of the car (Let denote it as F__{dg})

So the total force acting on the car is mathematically represented as

        F_{net} + F__{dg}} = F

Here this F representing the total force can be mathematically represented as

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So  at constant velocity

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=>    F =   0 \  N

So  

     F_{net} + F__{dg}} = 0

=>   F__{dg} }=  -F_{net}

=>   F__{dg} }=  -3674 \  N

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