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3 years ago

Is the following equation balanced? SO3 + 2H2O H2SO4 yes no

Physics

2 answers:

sergeinik [125]3 years ago

8 0

Answer:

Explanation:

it is not balanced because there are four oxygen atoms in H2SO4 while there 5 oxygen atoms in the reactants side. There are also more hydrogen atoms on the reactants side. To make it balanced remove the 2 in front of H2O. :)

Gnom [1K]3 years ago

5 0

No it is not balanced because there are four oxygen atoms in H2SO4 while there 5 oxygen atoms in the reactants side. There are also more hydrogen atoms on the reactants side. To make it balanced remove the 2 in front of H2O. :)

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Which is greater, the force exerted by the Earth on the Sun, or the force exerted by the Sun on the Earth? Why?

LekaFEV [45]

Answer:

There is no great force, the force exerted by the Earth on the Sun, and the force exerted by the Sun on the Earth are equal

Explanation:

By definition...

3 0

3 years ago

When the displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position, what fraction of the

KonstantinChe [14]

Answer:

The ratio is KE : TM = 0.75

Explanation:

from the question we are told that

The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

Generally the total mechanical energy of the mass is mathematically represented as

$TM = \frac{1}{2} * k * A^2$

Here k is the spring constant , A is the total displacement of the the mass from maximum compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

$TM = KE + PE$

=> $KE = TM - PE$

Here the potential energy of the mass is mathematically represented as

$PE = \frac{1}{ 2} * k * [ x ]^2$

Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is

$x = \frac{A}{2}$

$PE = \frac{1}{ 2} * k * [ \frac{A}{2} ]^2$

$KE = \frac{1}{2} * k * A^2 - \frac{1}{2} * k * [\frac{A}{2} ]^2$

=> $KE = \frac{1}{2} * k * A^2 - \frac{1}{8} * k * A ^2$

=> $KE = 0.375 * k * A^2$

So the ratio of $KE : TM$ is mathematically represented as

$\frac{KE}{TM} = \frac{0.375 k A^2 }{0.5 k A^2}$

=> $\frac{KE}{TM} = 0.75$

3 0

3 years ago

I select true helllpppp me

yanalaym [24]

Answer:

your right answer is true

hope it helps you

3 0

3 years ago

Read 2 more answers

There are two equations from which a change in the gravitational potential energy u of the system of a mass m and the earth can

Colt1911 [192]

The change in the gravitational potential energy is represented by the equation
u = ΔPE = Δmgh
since the mass of the system will remain constant and the acceleration due to gravity will also remain constant, the equation will become
u = mg Δh

5 0

3 years ago

What is the electric potential 12 cm away from a charge of –5.2 × 10^–6C?

MAXImum [283]

The equation for electric potential of a point charge is:

V=(k*q)/r where k=9*10^11 N m²/C², q is the charge and r is the distance from the charge to the point in which we are calculating the potential.

q=-5.2*10^-6 C
r=12 cm = 0.12 m

Now we plug in the numbers and get:

V=-3.9*10^5 Volts, so the correct answer is the second one.

8 0

3 years ago