Ask question

Ask question

All categories

bearhunter [10]

2 years ago

10

I just need an answer ASAP

2 answers:

nikdorinn [45]2 years ago

8 0

Answer: c

Explanation: hope this helps :)

seraphim [82]2 years ago

4 0

I may be wrong but d ?

You might be interested in

A train increase its speed steadily from 10ms to 20ms in 1 minutes

maxonik [38]

Answer:

Explanation: nigerian what

8 0

2 years ago

Initially a car accelerates at 2 m/s2 for x seconds. The car then travels at a velocity of -6 m/s for x seconds. If the car disp

Luda [366]

Answer:

The time travel is

t=8 s

Explanation:

$a= 2 \frac{m}{s^{2} } \\v=-6 \frac{m}{s} \\x=16m$

$x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}$

$x_{f}=0-6*t+\frac{1}{2} *2*t^{2}$

$t^{2}-6*t-16=0\\ using :\\\frac{-b+/-\sqrt{b^{2}-4*c*a } }{2} \\\frac{-(-6)+/-\sqrt{(-6)^{2}-4*(-16)*(1) } }{2}=\frac{3}{2} +/- \frac{10}{2} \\t_{1} = 2s \\t_{2} = 8s$

Check

$t_{2}=8s$

$x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}$

$x_{f}=0-6*+\frac{1}{2} *2*8^{2}$

$x_{f}=-48+64\\x_{f}=16$

5 0

3 years ago

The answer is -7m, but I don’t know how that’s the answer. Can anyone explain?

atroni [7]

Explanation:

At first it is in 14m position but position doesn't matter in displacement, similar case for time taken.

So at first it travels 6m in positive direction.

So displacement= 6m

Then it travels 13 in opposite or negative direction.

So displacement = 6 -13 m = -7 m

Hope it helps ya

8 0

2 years ago

Read 2 more answers

A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4

SIZIF [17.4K]

Answer:

The value is $v = 47 \ m/s$

Explanation:

From the question we are told that

The initial speed of the roller coaster is $u = 13 \ m/s$

The length of the hill is $l = 400 \ m$

The acceleration of the roller coaster is $a=4.0 \ m/s^2$

Generally the acceleration is mathematically represented as

$a = \frac{ v - u}{ t_f - t_i }$

Here $t_i$ is the initial time which is equal to zero

$v_f$ is the final velocity which is mathematically represented as

$v_f = \frac{d}{ t_f}$

So

$a = \frac{ \frac{d}{d_f} - u }{ t_f - t_i}$

$4 = \frac{\frac{400}{ t_f} - 13}{t_f - 0}$

$4 = \frac{400 - 13t_f}{ t_f} * \frac{1}{t_f}$

$4t_f ^2 +13f + 400 =$

Solving this using quadratic formula we obtain

$t_f = 8.5 \ s$

$t_f = -11.8 \ s$

Generally time cannot be negative so

$t_f = 8.5 \ s$

Generally the final velocity is mathematically represented as

$v = \frac{400}{8.5}$

$v = 47 \ m/s$

5 0

3 years ago

Which statements about radiocarbon dating are true?

seropon [69]

Radiocarbon saying assume the half life for radioistopes change over time. The half life of C -14 is 5730 years

8 0

3 years ago

Read 2 more answers