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Neporo4naja [7]
3 years ago
7

Calculate the period of wave whose frequency is 50Hz​

Physics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

0.02 sec

here.

frequency=50 Hz

we know that time period = 1/f

=1/50

=0.02sec

miss Akunina [59]3 years ago
5 0

Explanation:

time period= 1/frequency.

= 1/50 = 0.02 second.

hope this helps you.

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If a length and diameter of a pencil are both multiplied by 10, then the volume is multiplied by ?
Feliz [49]

Answer:

1000

Explanation:

If we model the pencil as a cylinder:

V = π r² h

Or, in terms of diameter:

V = π/4 d² h

If we multiply d and h by 10:

V = π/4 (10 d)² (10 h)

V = 1000 (π/4 d² h)

The volume increases by a factor of 1000.

5 0
3 years ago
A child’s toy rake is held so that its output arm is 0.75 meters. If the mechanical advantage is 0.33, what is
Masja [62]
Input= ?
Output= 0.75
MA= 0.33

So I just kept on Dividing numbers until I was close to "0.33" & I cam up with the answer of .......... 0.25.


So when you divide 0.25 by 0.75 you get the MA of 0.33 
4 0
3 years ago
uniform solid sphere of radius R rotates about a diameter with an angular speed 536 radians/second. The sphere then collapses un
weeeeeb [17]

Answer:

2144 rad/s

Explanation:

R1 = R

ω1 = 536 rad/s

R2 = R/2

ω2 = ?

Mass is M

By use of angular momentum remains constant if no external force is acting on the body.

I1 ω1 = I2 ω2

The moment of inertia of solid sphere is 12/5 MR^2

So, 2/5 x M R^2 x 536 = 2/5 x M (R/2)^2 x ω2

536 = ω2 / 4

ω2 = 2144 rad/s

4 0
3 years ago
Read 2 more answers
The accepted standard measurement for mass is the A) liter. B) pound. C) Newton. D) kilogram.
andreev551 [17]
D) Kilograms is the standard unit of mass
6 0
3 years ago
Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 re
alexgriva [62]

Answer:

\frac{Ie}{lm} = 1.10*10^{-3}

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

\frac{Ie}{lm} = \frac{-N}{(nf-ni)}

\frac{Ie}{lm} = \frac{-(-4.2)}{(12125 - (8325))}

\frac{Ie}{lm} = 1.10*10^{-3}

5 0
3 years ago
Read 2 more answers
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