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Neporo4naja [7]
3 years ago
7

Calculate the period of wave whose frequency is 50Hz​

Physics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

0.02 sec

here.

frequency=50 Hz

we know that time period = 1/f

=1/50

=0.02sec

miss Akunina [59]3 years ago
5 0

Explanation:

time period= 1/frequency.

= 1/50 = 0.02 second.

hope this helps you.

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If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m
musickatia [10]

Answer:

The correct solution is "14.6875 kg".

Explanation:

Given values:

Force,

F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,

⇒ Force=Mass\times Acceleration

or,

⇒       F=ma

⇒    47.0=m\times 3.20

⇒       m=\frac{47.0}{3.20}

⇒           =14.6875 \ kg

4 0
2 years ago
List three cases in which potential energy becomes
olga55 [171]
1 Electrical Potential Energy, separating two charged plates will store energy as the plates want to return to their original position. 

<span>2 Spring or Elastic can be stretched to store energy as it wants to return to rest </span>

<span>3 Gravitational energy is stored by moving something (ball or pendulum are both examples of this) against a gravity gradient (lifting an object) that wants to fall back down. </span>
5 0
3 years ago
Stars appears to move from east to west because
Liula [17]

Answer:

The earth rotates from West to east

Explanation:

  • Every planet in our solar system rotates around their axis in West to east direction.
  • Only Venus is the only planet which rotates from east to west
8 0
2 years ago
Read 2 more answers
Calculate V1 and V2 ( V = voltage )
Kitty [74]

FORMULA:

  • V = IR, where V = P.D; I = Current; R = Resistance.

ANSWER:

Total equivalent resistance for circuit:

R(eq) = R1 + R2 [It is in series]

  • 330Ω + 470Ω
  • 800Ω

Now, Current passing through whole circuit:

I = V/R

  • 16/800
  • 1/50 ampere

We know that, In series combination current passing through whole circuit is same.

So, V¹ = IR¹

V¹ = 1/50 × 330

  • V¹ = 6.6 volt

And V² = IR²

V² = 1/50 × 470

  • V² = 9.4 volt
7 0
3 years ago
Read 2 more answers
A star near the visible edge of a galaxy travels in a uniform circular orbit. It is 41,200 ly (light-years) from the galactic ce
Ronch [10]

The total mass of the galaxy is 443.4 Solar mass

Orbital velocity (v) = \sqrt{\frac{MG}{R} }

where M= weight of galaxy

G= gravitational constatnt = 6.674*10^-^1^1 (given)

R = distance from centre = 41200 Light years (given)= 4.12*9.5*10^1^6  km (1 ly= 9.5*10^3 billion km)

v= orbital velocity = 275  km/s (given)

∴ According to the formula

(2.75*10^2)^2 = \frac{M*6.674*10^-^1^1}{4.12*9.5*10^1^6}

⇒ 7.56*10^4*4.12*9.5*10^1^6=M*6.674*10^-^1^1 (cross multiplying and expanding)

⇒ 29.59*10^2^1=M*6.674*10^-^1^1

⇒ \frac{29.59*10^2^1*10^1^1}{6.674}=M

⇒ 4.434*10^3^2=M

1 solar mass = 1.989*10^3^0 kg

⇒ Mass in solar mass =443.4 Solar mass

⇒ M = 443.4 Solar mass

Learn more about Orbital velocity here :

brainly.com/question/22247460

#SPJ10

6 0
2 years ago
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