The body moves at a velocity of 1.62m/s after the bullet emerges.
<h3>Given:</h3>
Mass of bullet, 
= 22g
= 0.022 kg
Mass of the block, 
= 1.9 kg
Velocity of bullet , 
= 265 m/s
According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.
After penetration;
The formula for calculating the collision of a body is expressed as:
p = mv
m is the mass of the body
v is the velocity of the body
∴ Momentum before = Momentum after
Substitute the given parameters into the formula as shown:
Therefore, It moves with a velocity of 1.62 m/s.
Learn more about momentum here:
brainly.com/question/25121535
#SPJ1
a) 
For a gas transformation occuring at a constant pressure, the work done by the gas is given by
where
p is the gas pressure
V_f is the final volume of the gas
V_i is the initial volume
For the gas in the problem,
is the pressure
is the initial volume
is the final volume
Substituting,
b) 
The heat absorbed by the gas can be found by using the 1st law of thermodynamics:
where
is the change in internal energy of the gas
Q is the heat absorbed
W is the work done
Here we have
So we can solve the equation to find Q:
And this process is an isobaric process (=at constant pressure).
D. Assuming that it doesn’t accelerate and then decelerate between seconds.
A. Their displacement is the same, zero miles.
