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Bess [88]
3 years ago
13

If a sample of gas has a volume of 5.00 L @ 92.3 C, what will the volume of the gas be if the temperature is lowered to -37 C

Chemistry
1 answer:
timurjin [86]3 years ago
8 0
You can apply Charles' Law. 
V1= 5.00 (L)
T1= 92.3 + 273 = 365.3 (K)
T2= -37 + 273 = 236 (K)
V2 = ? (L)

We have: V1/T1 = V2/T2 
--> V2= (V1*T2)/T1 = (5*236)/365.3 = 3.23 (L)
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20.352 mL of chlorine under a pressure of 680. mm Hg are
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Answer:

0.01144L or 1.144x10^-2L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 20.352 mL

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Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:

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Divide both side by 1210

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Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:

1000mL = 1 L

11.44mL = 11.44/1000 = 0.01144L

Therefore the volume of the container is 0.01144L or 1.144x10^-2L

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